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4 years ago

What is the entropy of isolated system?

Physics

1 answer:

melamori03 [73]4 years ago

7 0

Answer: Entropy is the measure of the disorder of a system

Explanation:

Entropy is a thermodynamic quantity defined as a criterion to predict the evolution or transformation of thermodynamic systems. In addition, it is used to measure the degree of organization of a system.

In other words: Entropy is the measure of the disorder of a system and is a function of state. That is, it depends only on the state of the system.

However, in the case of an isolated system in an <u>irreversible process</u>, the value of entropy increases in the course of a process that occurs naturally. While in a <u>reversible process</u> the entropy of the isolated system remains constant.

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Can someone please help me with these 2 questions

jok3333 [9.3K]

1. Answer: 7.75 seconds
Explanation: 76-14=62 metres
62/8=7.75 seconds

2. Answer: 2.5 seconds
Explanation: 28-18=10 metres
10/4=2.5 seconds

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4 years ago

A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3.0 m is initially at rest. A 20 kg boy approaches the m

nekit [7.7K]

Answer:

The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s

Explanation:

The rotational inertia of the merry-go-round = 600 kg·m²

The radius of the merry-go-round = 3.0 m

The mass of the boy = 20 kg

The speed with which the boy approaches the merry-go-round = 5.0 m/s

$F_T \cdot r = I \cdot \alpha = m \cdot r^2 \cdot \alpha$

Where;

$F_T$ = The tangential force

I = The rotational inertia

m = The mass

α = The angular acceleration

r = The radius of the merry-go-round

For the merry go round, we have;

$I_m \cdot \alpha_m = I_m \cdot \dfrac{v_m}{r \cdot t}$

$I_m$ = The rotational inertia of the merry-go-round

$\alpha _m$ = The angular acceleration of the merry-go-round

$v _m$ = The linear velocity of the merry-go-round

t = The time of motion

For the boy, we have;

$I_b \cdot \alpha_b = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Where;

$I_b$ = The rotational inertia of the boy

$\alpha _b$ = The angular acceleration of the boy

$v _b$ = The linear velocity of the boy

t = The time of motion

When the boy jumps on the merry-go-round, we have;

$I_m \cdot \dfrac{v_m}{r \cdot t} = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Which gives;

$v_m = \dfrac{m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t} \cdot r \cdot t}{I_m} = \dfrac{m_b \cdot r^2 \cdot v_b}{I_m}$

From which we have;

$v_m = \dfrac{20 \times 3^2 \times 5}{600} = 1.5$

The velocity of the merry-go-round, $v_m$ , after the boy hops on the merry-go-round = 1.5 m/s.

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3 years ago

Elements produce their spectrum when their electrons _____.

Aleonysh [2.5K]

The correct answer is the third one: move toward the ground state. Remember please that Elements produce their spectrum when their electrons move toward the ground state. Hope this is very useful

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4 years ago

As an adult, what is the best way to remain healthy?

Zigmanuir [339]

1. Eat a balanced diet and regular exercise. This is the best way because eating right and exercising are is more beneficial than just exercising.

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3 years ago

Read 2 more answers

In one experiment, the teacher determined that the force on the wire was 2.14 mN

blsea [12.9K]

Answer:

in ine experiment the teacher determined

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3 years ago