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timofeeve [1]
4 years ago
6

What is the entropy of isolated system?

Physics
1 answer:
melamori03 [73]4 years ago
7 0

Answer: Entropy is the measure of the disorder of a system

Explanation:

Entropy is a thermodynamic quantity defined as a criterion to predict the evolution or transformation of thermodynamic systems. In addition, it is used to measure the degree of organization of a system.

In other words: Entropy is the measure of the disorder of a system and is a function of state. That is, it depends only on the state of the system.  

However, in the case of an isolated system in an <u>irreversible process</u>, the value of entropy increases in the course of a process that occurs naturally. While in a <u>reversible process</u> the entropy of the isolated system remains constant.

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Read 2 more answers
Two blocks connected by a light string are being pulled across a frictionless horizontal tabletop by a hanging 16.2-N weight (bl
Artemon [7]

Newton's second law allows us to find the results for the string tensions are:

  • T₁ = 6.7 N
  • T₂ = 16.54 N

Newton's second law gives a relationship between force, mass and acceleration of bodies

            ∑ F = ma

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration.

Free-body diagrams are representations of the forces applied to bodies without the details of them.

The reference system is a coordinate system with respect to which the forces decompose, in this case the x-axis is parallel to the plane and the positive direction in the direction of movement, the y-axis is perpendicular to the plane.

In the attachment we see a free-body diagram of the three-block system.

Let's apply Newton's second law to each body.

Block C

Y-axis

       W_c -T_2 = m_c a

Block A

X axis  

       T_2 - T_1 - W_a_x = m_a a  

Y axis  

       N_a - W_a_y = 0  

Block B

X axis

      T_1 - W_b_x = m_b a  

Y axis

      N_b - W_b_y =0

Let's  use trigonometry to find the components of the weight.

Block A

         cos θ = \frac{W_a_y}{W_a}  

         sin θ = \frac{W_a_x}{W_a}

         W_a_y = W_a cos \theta

         W_a_x= W_a sin \theta

Block B

        cos θ = \frac{W_b_y}{W_b}

        sin θ =  \frac{W_b_x}{W_b}

        W_b_y = W_b cos \theta \\W_b_x = W_b sin \theta

Let's write our system of equations.

     W_c - T_2 = m_c a \\           T_2 - T_1 - W_a_x = m_a a \\T_1 - W_b_x = m_b a

 

Let's find the acceleration of the bodies, adding the equations.

     W_c - W_a_x - W_b_x = ( m_a+m_b+m_c) a\\  

         

The weight is

    W = mg

Let's  substitute

         (m_c - m_a -m_b ) g \ sin \theta = ( m_c+m_a+m_b)  \ a  \\a= \frac{ m_c-m_a-m_b  }{ m_a+m_b+m_c} \ g sin \theta

Indicate ma mass of the block a ma = 1.00 kg, the mass of the block b mb = 2.2 kg and the weight of the block c Wc = 16.2 N, let's find the mass of block c.

          m_c = Wc / g

          m_c = 16.2 / 9.8

          m_c = 1.65 kg

we substitute the values

          a= \frac{1.65 -2.20 -1.00}{1.65+2.20+1.00} \ 9.8 \ sin \theta  \\a= -0.3096 sin \theta

The negative sign indicates that the system is descending, to be able to give a specified value an angle is needed, they assume that the angle of the ramp is 45º

          a = - 0.3196 sin 45

          a = -0.226 m / s

Taking the acceleration we are going to look for the tensions.

From the equation of block C

           W_c - T_2 = m_c a \\T_2 = m_c ( g-a)\\T_2 = 1.65 ( 9.8 + 0.226)

            T₂ = 16.54 N

From the equation of block B

          T_1 - W_b_x = m_b a\\T_1 = m_b (a + g sin \theta)\\T_1 = 1.00 (-0.226 + 9.8 \ sin 45)

           T₁ = 6.7 N

In conclusion using Newton's second law we can find the results for the string tensions are:

  •  T₁ = 6.7 N
  •  T₂ = 16.54 N

Learn more here:  brainly.com/question/20575355

7 0
3 years ago
If light energy to electric energy conversion using solar cells is 12 % efficient, how many square miles of land must be covered
umka2103 [35]

Complete Question

The light energy that falls on a square meter of ground over the course of a typical sunny day is about 20 MJ . The average rate of electric energy consumption in one house is 1.0 kW .

If light energy to electric energy conversion using solar cells is 12 % efficient, how many square miles of land must be covered with solar cells to supply the electrical energy for 350000 houses? Assume there is no cloud cover.

Answer:

The area is  A = 1.26 *10^{7} m^2

Explanation:

From the question we are told that

      The efficiency is  \eta =12%

      The number of houses is  N = 350000

       The light energy per day is E =  20 \ MJ

       The average rating of electric energy for a house is  E_h  =  1.0 \ k W =  1000W

   

Generally the electric energy which the solar cells covering 1 \ m^2 produces in a day is

       E_s =  \eta * E

           E_s =  0.12 * 20*10^{6}

          E_s = 2.4 MJ m^{-2}

Energy for required by one house for one day is  

        E_H  = E_h * 1 \ day  

       E_H  = 1000 * 24 * 3600  

        E_H  = 86.4 MJ

Energy needed for 350000 house is

      E_z = 86.4 *10^{6} *  350000  

     E_z = 3.02 *10^{7} MJ

The area covered is mathematically represented as

            A = \frac{3.02*10^{7} \ MJ}{2.4 \ MJ m^{-2}}

           A = 1.26 *10^{7} m^2

           

       

5 0
3 years ago
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