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DanielleElmas [232]
4 years ago
8

A) Cu2+ + Bu?

Chemistry
1 answer:
sergejj [24]4 years ago
5 0

Answer:

I and K cannot be intepreted. I think theres something wrong in the scanning. Besides that i hope this helps

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What is the molar mass for 5 mol Na
zimovet [89]

Answer:

22.98977 g/

Brainliest please

4 0
3 years ago
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What is the volume occupied by 0.106 mol of helium gas at a pressure of 0.99 atm and a temperature of 309 K ?
iris [78.8K]
0.99 x volume= 0.106 x 0.082 x 309
volume= 2.71 ml
6 0
4 years ago
A chemist adds of a sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemi
schepotkina [342]

This is a incomplete question.The complete question is:

A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: 50.4 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of sodium thiosulfate solution = 1.77 M

Volume of sodium thiosulfate solution = 180.0 mL = 0.1800 L

Putting values in equation 1, we get:

\text{Moles of sodium thiosulfate}={1.77}\times{0.1800}=0.319moles

Mass of sodium thiosulfate = moles\times {\text {Molar mass}}=0.319moles\times 158.11g/mol=50.4g

Thus 50.4 g of sodium thiosulfate the chemist has added to the flask.

6 0
3 years ago
What does chemlcal change mean
Ronch [10]

Answer:

a chemical change is a change that changes the substance into a whole new substance.

Examples include: burning wood, a banana peel rotting, milk souring, and even your food/drinks digesting.

8 0
3 years ago
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An electrochemical cell is powered by the half reactions shown below.
andrezito [222]
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation. 

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign. 

Pb(s) --> Pb2+ +2e-      E0 = +0.13 V
Ag+ + e-  ---> Ag           E0 = +0.80 V

Adding up the E0's would yield an overall electric cell potential of +0.93 V.
7 0
4 years ago
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