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DanielleElmas [232]
4 years ago
8

A) Cu2+ + Bu?

Chemistry
1 answer:
sergejj [24]4 years ago
5 0

Answer:

I and K cannot be intepreted. I think theres something wrong in the scanning. Besides that i hope this helps

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7) If the mass of an object is 20 g and its volume is 25 L. What is the density of this object? 1 8) What is the difference betw
Nataly_w [17]
Sorry i have a test and need points love u
4 0
3 years ago
Read 2 more answers
All organic molecules have what element in common
joja [24]

Every organic molecules/compound contains carbon (c).

Some other very abundant are hydrogen, nitrogen, oxygen, phosphorus, and sulfur.

I learned this with the acronym CHNOPS.

C - Carbon

H - Hydrogen

N - Nitrogen

O - Oxygen

P - Phosphorus

S - Sulfur

Hope this helps!


6 0
3 years ago
Read 2 more answers
The atomic weight of copper is 63.546 amu. The two naturally occuring isotopes of copper have the following masses 63Cu, 62.9298
strojnjashka [21]

Answer:

The percent isotopic abundance of Cu-65 is 30.79 %.

The percent isotopic abundance of Cu-63 is 69.21 %.

Explanation:

we know there are two naturally occurring isotopes of carbon, Cu-63 (62.9298 amu)  and Cu-65 (64.9278 amu)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 62.9298 amu

1-x for isotopes having mass 64.9278 amu

The average atomic mass of copper is 63.546 amu.

we will use the following equation,

62.9298 x + 64.9278 (1-x) = 63.546

62.9298x +  64.9278 -  64.9278x = 63.546

62.9298x - 64.9278x = 63.546  - 64.9278

-1.998 x = -1.3828

x=-1.3828 / -1.998

x= 0.6921

0.6921 × 100 = 69.21 %

69.21 % is abundance of Cu-63 because we solve the fraction x.

now we will calculate the abundance of Cu-65.

(1-x)

1-0.6921 = 0.3079

0.3079 × 100 = 30.79 %

30.79 % for Cu-65.

6 0
3 years ago
3. Which of the following is the correct mathematical expression to use to
xxTIMURxx [149]

Answer:

The pH of a 0.10 Maqueous Ba(OH)2 solution at 25°C is 13.30

Explanation:

The balanced equation is Ba(OH)2(s)→Ba2++2OH−

This indicates that the concentration is 0.2 M

We will find H+ ion concentration

As we know that

[H+][OH−]=1.0×10−14M

Given -  

[OH−]=2.0×10−1M

Putting value of [OH-] in above equation we get -  

[H+]=5.0×10−14M

pH=−log10[H+]

pH=−log10[5.0×10−14] = 13.30.

8 0
3 years ago
Determine the mass of 1 mol of gold (Au), of aluminum chloride (AlCl3), and of glucose (C6H12O6)
sleet_krkn [62]

Answer: Mass of 1 mol of gold (Au) is 197g , of aluminum chloride(AlCl_3) is 133.5 g and of glucose (C_6H_{12}O_6) is 180 g

Explanation:  Mass of 1 mole of a substance is called its molar mass.

a) 1 mole of Au contains 6.023\times 10^{23}atoms and weigh 197g.

b) 1 mole of AlCl_3 will weigh=1\times {\text {mass of 1 mole of Aluminium}}+3\times {\text {mass of 1 mole of chlorine atom}}

Thus mass of 1 mole of AlCl_3 will be =1moles\times {27g/mol}+3moles\times {35.5g/mol}=133.5g

c) 1 mole of C_6H_{12}O_6 will weigh=6\times {\text {mass of 1 mole of carbon}}+12\times {\text {mass of 1 mole of hydrogen atom}}+6\times {\text {mass of 1 mole of oxygen}}

1 mole of C_6H_{12}O_6 will weigh=6\times 12g/mol+12\times 1g/mol+6\times 16g/mol=180g


5 0
4 years ago
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