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ikadub [295]
3 years ago
8

An electrochemical cell is powered by the half reactions shown below.

Chemistry
1 answer:
andrezito [222]3 years ago
7 0
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation. 

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign. 

Pb(s) --> Pb2+ +2e-      E0 = +0.13 V
Ag+ + e-  ---> Ag           E0 = +0.80 V

Adding up the E0's would yield an overall electric cell potential of +0.93 V.
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natka813 [3]

Answer:

B

Explanation:

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a gas at 155 kPa and 25 degrees C occupies a container with an initial volume of 1.00 L. By changing the volume, the pressure of
Ne4ueva [31]
First thing, you convert from kPa to Pa. Then, you find the atm value of the Pa you got.

155 kPa = 155 000 Pa
1 atm = 101 325 Pa
x atm = 155 000 Pa
You divide 101 325 over 155 000 and you get about 1.53
So, 155 000 Pa = 1.53 atm.
So, T (temperature) = 25 + 273 = 298

605 kPa = 605 000 Pa
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x atm = 605 000 Pa
You divide 605 000 over 101 325 and you get about 5.97 
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P1 * V1/T1 = P2 * V2/T2
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Hope this Helps :)
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Potassium and bromine combine to make KBr. What is the name of this compound?
makkiz [27]
The name is Potassium bromide.
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What is the coefficient of Ca(OH)2 in the equation Ca(OH)2 + HNO3 → Ca(NO3)2 + H2O when balanced using the smallest possible coe
Vikentia [17]

Answer:

The coefficient of Ca(OH)2 is 1

Explanation:

Step 1: unbalanced equation

Ca(OH)2 + HNO3 → Ca(NO3)2 + H2O

Step 2: Balancing the equation

On the right side we have 2x N (in Ca(NO3)2 ) and 1x N on the left side (in HNO3). To balance the amount of N on both sides, we have to multiply HNO3 by 2.

Ca(OH)2 + 2HNO3 → Ca(NO3)2 + H2O

On the left side we have 4x H (2xH in Ca(OH)2 and 2x H in HNO3), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side, by 2.

Now the equationis balanced.

Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O

The coefficient of Ca(OH)2 is 1

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