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dangina [55]
3 years ago
14

A chemist adds of a sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemi

st has added to the flask. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
schepotkina [342]3 years ago
6 0

This is a incomplete question.The complete question is:

A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: 50.4 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of sodium thiosulfate solution = 1.77 M

Volume of sodium thiosulfate solution = 180.0 mL = 0.1800 L

Putting values in equation 1, we get:

\text{Moles of sodium thiosulfate}={1.77}\times{0.1800}=0.319moles

Mass of sodium thiosulfate = moles\times {\text {Molar mass}}=0.319moles\times 158.11g/mol=50.4g

Thus 50.4 g of sodium thiosulfate the chemist has added to the flask.

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The equation for the reaction between KOH and HCl is as follows
KOH + HCl ---> KCl + H2O
the stoichiometry of KOH to HCl = 1:1
the number of KOH moles reacted = 0.5 mol /1000 cm³ * 30 cm³ 
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the number of HCl moles reacted = number of KOH moles reacted 
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0.2 mol of HCl in - 1000 cm³
Therefore volume required for 0.015 mol = 1000 cm³ / 0.2 mol * 0.015 mol 
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