2×5^{2} if you don't understand its 2 times 5 to the second power.
There's more ways than one to solve this, just as there's more ways than one to skin a cat.
Two paralle lines have the same slope, so the desired new line looks exactly like the given line 3x + 5y = 6, except that the constant, 6, is replaced by another value.
Write out 3x + 5y = c
Replace x with 0 and y with 3. Then 3(0) + 5(3) = c, and c = 15.
Thus, the equation of the new, parallel, line is 3x + 5y = 15.
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
The expression in company B represents that is is in arithmetic progression where first term is 42000 and common difference is 1800 . So we have to use the formula of sum of n terms which is
Where a is the first term, n is the nth term, d is the common difference
On substituting there values,we will get
= 15(84000+52200) = 15*136200 =2043000
And for company A, it is
Difference between them =2043000-2002500= 40500
So the correct option is the second option .
Hello,
there are some words that I could not read. But:
I support evements are independants.
p(s)=0.2
p(l)=1-0.2=0.8 l=lose
1)0.8*0.2=0.16
2) 0.8²*0.2=0.128
3) 0.8^3*0.2=0.1024
4) 0.2*0.8^(n-1)
