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NemiM [27]
3 years ago
15

Which of the following group 7A elements is the most reactive ?

Chemistry
2 answers:
LiRa [457]3 years ago
6 0
I'm Pretty sure but not 100% certain....
I think it's B. Iodine
Scrat [10]3 years ago
3 0
C) Fluorine is the most reactive among halogens
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In your own words, describe the purpose of using a chemical equation.<br><br> PLEASEEEE HURRY
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Hey mate, here is your answer. Hope it helps you.

Explanation:

To show how substances in a chemical reaction interact and to keep track of all elements and the number of atoms in each element on each side of the equation.The purpose of writing a balanced chemical equation is to know: the reactants (starting material) and products (end results) that occur. the ratios in which they react so you can calculate how much reactants you need and how much products can be formed.

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What is callibration of temperature
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What is Temperature Calibration? Temperature calibration refers to the calibration of any device used in a system that measures temperature. Most importantly, this usually means the temperature sensor, itself, which is typically a platinum resistance thermometer (PRT or PT-100), thermistor, or thermocouple.

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How do the physical and chemical properties the halogens compare with those of the noble gases? ​
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Explanation:

To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. ... The halogens tend to be very reactive, while the noble gases are in no way reactive and don't bond easily, if at all.

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2 years ago
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In a constant pressure calorimeter, the temperature of 60.0 g of water increases by 4.50c. What amount of heat is transferred to
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3 years ago
A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,
Scorpion4ik [409]

<u>Answer:</u> The value of K_c is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For Sb_2S_3</u>

Given mass of Sb_2S_3 = 1.00 kg = 1000 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of Sb_2S_3 = 339.7 g/mol

Putting values in equation 1, we get:

\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol

  • <u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

                  Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)

Initial:            2.944      5

At eqllm:      2.944-x     5-3x         2x        3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}

The expression of K_c for above equation, we get:

K_c=\frac{[H_2S]^3}{[H_2]^3}

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412

Hence, the value of K_c is coming out to be 0.412

3 0
3 years ago
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