Answer:
Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)
1.35 V
Explanation:
Given that the reduction potential of
Cu^2+(aq) + e- -----> Cu^+(aq) is +0.15 V
While the reduction potential of
Au3+(aq) + 3 e- -----> Au(s) is + 1.50V
It is clear that the Cu^+(aq)/Cu^2+(aq) system is the anode while Au^3+(aq)/Au(s) system is the cathode based on the reduction potentials shown above. The number of electrons transferred (n) =3
E°cell = E°cathode - E°anode
E°cell= 1.50-0.15
E°cell= 1.35 V
Answer:
- <u><em>3.30 × 10³ years</em></u>
Explanation:
1) <u>Carbon-14 disintegration rate of a young (alive) tree</u>: 0.266 per second per gram.
2)<u> Carbon-14 disintegration rate of a wood sample prepeared from an object recovered at an archaelogical excavation (dead matter):</u> 0.178 per second per gram.
3) <u>Ratio of decay</u>: A/A₀ = 0.178 / 0.266 = 0.669
4) <u>Half-life equation</u>: A/A₀ = (1/2)ⁿ, where n is the number of half-lives since the object died.
5) <u>Substitute and solve for n</u>:

That means that 0.578 half-life has elapsed since the wood with which the object was created was dead matter.
6) <u>Convert number of half-lives to years</u>:
- 0.578 half-life × 5715 years/half-life = 3,303 years = 3.30 × 10³ years.
Water is the answer because the word <span>Hydroelectric has hydro in it and hydro= water.</span>
I hope this helps answer some of your questions.