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Lera25 [3.4K]
2 years ago
15

(b) If 45.0% of the ethanol that did not produce the ether reacts by the side reaction, what mass (g) of ethylene is produced?

Chemistry
1 answer:
Finger [1]2 years ago
3 0

Ethylene is a hydrocarbon which has the formula C ₂H ₄ or H₂C=CH₂. It is a colourless flammable gas with a faint "sweet and musky" odour when pure. It is the simplest alkene.

Ethylene is widely used in the chemical industry, and its worldwide production exceeds that of any other organic compound.

<h3>What is ethylene used for?</h3>

Medical: Ethylene is used as an anaesthetic. Metal Fabrication: Ethylene is used as oxy-fuel gas in metal cutting, welding and high velocity thermal spraying. Refining: Ethylene is used as refrigerant, especially in LNG liquefaction plants. Rubber & Plastics: Ethylene is used in the extraction of rubber.

<h3>Is ethylene harmful to humans?</h3>

* Ethylene gas can affect you when breathed in. * Skin contact with liquid Ethylene can cause frostbite. * Exposure to Ethylene can cause headache, dizziness, fatigue, lightheadedness, confusion and unconsciousness. * Ethylene is a HIGHLY FLAMMABLE and REACTIVE chemical and a DANGEROUS FIRE and EXPLOSION HAZARD.

Learn more about ethylene here:

<h3>brainly.com/question/27566273</h3><h3 /><h3>#SPJ4</h3>
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The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P
Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Pb: 207.2;
  • S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is \rm PbS. There will be 890 grams of \rm PbS in one kilogram of this rock.

Formula mass of \rm PbS:

M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}.

How many moles of \rm PbS formula units in that 890 grams of \rm PbS?

\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol.

There's one mole of \rm Pb in each mole of \rm PbS. There are thus \rm 3.71980\; mol of \rm Pb in one kilogram of this rock.

What will be the mass of that \rm 3.71980\; mol of \rm Pb?

m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg.

In other words, the \rm PbS in 1 kilogram of this rock contains \rm 0.770743\; kg of lead \rm Pb.

How many kilograms of the rock will contain enough \rm PbS to provide 1.5 kilogram of \rm Pb?

\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg.

5 0
4 years ago
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