Answer:
the heat of formation of isopropyl alcohol is -317.82 kJ/mol
Explanation:
The heat of combustion of isopropyl alcohol is given as follows;
C₃H₇OH (l) +(9/2)O₂ → 3CO₂(g) + 4H₂O (g)
The heat of combustion of CO₂ and H₂O are given as follows
C (s) + O₂ (g) → CO₂(g) = −393.50 kJ
H₂ (g) + 1/2·O₂(g) → H₂O (l) = −285.83 kJ
Therefore we have
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ which we can write as
3C (s) + 3O₂ (g) → 3CO₂(g) = −393.50 kJ × 3 =
4H₂ (g) + 2·O₂(g) → 4H₂O (l) = −285.83 kJ × 4
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ = +2006 kJ/mol
-1180.5 - 1143.32 +2006 = -317.82 kJ/mol
Therefore, the heat of formation of isopropyl alcohol = -317.82 kJ/mol.
Answer:
It is a example of erosion
Explanation: because pieces of rock erode making it unstable a causes a landslide
.15 liters of normal saline will drip into the patient's IV per hour.
Answer:
The answer to your question is letter B
Explanation:
A.) 2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 4
2 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
B.) 2 AgCl + Na2S ⟶ Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 2
2 Cl 2
2 Na 2
1 S 1
This reaction is balanced
C.) AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
1 Ag 4
1 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
D.) 2 AgCl + 2 Na2S ⟶ Ag2S + NaCl
Reactants Elements Products
2 Ag 4
2 Cl 1
4 Na 1
2 S 1
This reaction is unbalanced
The chemical equation for this reaction is this:
CO2 + 4H2 = CH4 + 2H2O
from the equation, the mole ration of CO2 to CH4 is ratio 1:1
and CH4 = 25.1
The mole ratio of H2 to H2O is 4:2
therefore, mole of H2 = 19.1* 4/2 = 38.2
The moles of methane produced is 38.2 moles
