Question

For the reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2 H 2 O ( g ) ↽ − − ⇀ 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found to be [H2O]=0.250 M, [ H 2 O ] = 0.250 M, [H2]=0.360 M, [ H 2 ] = 0.360 M, and [O2]=0.750 M. [ O 2 ] = 0.750 M. What is the equilibrium constant for this reaction?

Answer 1

Answer:

Kc = 1.55

Explanation:

This is the reaction:

       2H₂O (g)  ⇄    2H₂(g)    +     O₂(g)

Eq.   0.250M        0.360M          0.750M

The expression for Kc is.

Kc = [O₂] . [H₂]² / [H₂O]²

Kc = 0.750 . 0360² / 0.250²

Kc = 1.55