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exis [7]
3 years ago
8

For the reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2 H 2 O ( g ) ↽ − − ⇀ 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found

to be [H2O]=0.250 M, [ H 2 O ] = 0.250 M, [H2]=0.360 M, [ H 2 ] = 0.360 M, and [O2]=0.750 M. [ O 2 ] = 0.750 M. What is the equilibrium constant for this reaction?
Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

Kc = 1.55

Explanation:

This is the reaction:

       2H₂O (g)  ⇄    2H₂(g)    +     O₂(g)

Eq.   0.250M        0.360M          0.750M

The expression for Kc is.

Kc = [O₂] . [H₂]² / [H₂O]²

Kc = 0.750 . 0360² / 0.250²

Kc = 1.55

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3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
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LUCKY_DIMON [66]

Answer:

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The answer is 35.4335

Hope this helped! (Plz mark me brainliest!)

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