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Oduvanchick [21]
3 years ago
8

Why are group 1 elements more reactive than group 2 elements?

Chemistry
2 answers:
sashaice [31]3 years ago
4 0

Answer:

its because in group 2 elements,outermost electron is difficult to be removed than group 1 elements

Hence group 2 elements are less reactive than group 1

kaheart [24]3 years ago
3 0
Less reactive than Group<span> I </span>elements<span>. The reasoning for this is because it is </span>more<span> difficult to lose two electrons compared to losing just </span>one<span> electron. They mostly React with water to form alkaline solutions. ...Now This is because the smaller an atom the closer the outer electrons are to the nucleus.</span>
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what is the molarity of a RbOH solution if 60.0 mL of the solution is neutralized by 52.8 mL of a 0.5M HCl solution (Hint: Ma x
Dahasolnce [82]
RbOH is a strong base that dissociates completely and HCl is a strong acid that too dissociates completely. the complete reaction between the acid and base is;
RbOH + HCl ---> RbCl + H₂O
stoichiometry of acid to base is 1:1
At neutralisation point
H⁺ mol = OH⁻ mol
mol = molarity x volume 
if Ma - molarity of acid and Va - volume of acid reacted
Mb - molarity of base and Vb - volume of base reacted 
Ma x Va = Mb x Vb
0.5 M x 52.8 mL = Mb x 60.0 mL 
Mb = 0.44 M 
molarity of base - 0.44 M 

7 0
3 years ago
What is the thermal energy needed to completely melt 9.60 mol of ice at 0.0 C
inysia [295]
The  thermal energy  needed to  completely  melt  9.60  mole  of ice  at  0.0 C  is    57.8   Kj

        Explanation
ice  melt  to  form   water

The molar  heat of fusion  for   water  is  6.02  Kj/mol
Thermal energy =  moles  x  molar  heat  of  fussion  for water

=9.6  mol  x6.02 kj/mol =57.8  Kj
4 0
3 years ago
Read 2 more answers
The labels have fallen off three bottles containing powdered samples of metals; one contains zinc, one lead, and the other plati
Alinara [238K]

Here we have to identify the metal powder by the given disposal.

The identification of Zinc can be done by 1 m nitric acid (HNO₃) and Ni(NO₃)₂ which will produce hydrogen gas by reaction and displacement reaction as shown below.

Zn + 2 HNO₃ = Zn(NO₃)₂ + H₂ (g)

Zn + Ni(NO₃)₂ = Zn(NO₃)₂ + Ni

The identification of lead can be done by the reaction with 1 m nitric acid (HNO₃) which produces lead nitrate.

The reaction is-

Pb + 4HNO₃ = Pb(NO₃)₂ + 2NO₂ + 2H₂O

The identification of platinum can be done by the reaction with all the given disposal as it will not react with any of the compound.

1. Identification of Zinc (Zn):

(a) Zn metal will not react with sodium nitrate (NaNO₃) as sodium remains at the lower position of the activity series than zinc.

Zn + NaNO₃ = No reaction

(b) Zn metal will react with 1 m HNO₃ to form hydrogen gas. The reaction is:

Zn + 2 HNO₃ = Zn(NO₃)₂ + H₂ (g)

(c) Zn will react with nickel nitrate [Ni(NO₃)₂] because it may only cause displacement reaction the reduction potential of Zn²⁺/Zn (-0.76) is less than that of Ni²⁺/Ni (-0.23). Thus the reaction will be:

Zn + Ni(NO₃)₂ = Zn(NO₃)₂ + Ni

2. Identification of lead (Pb):

(a) Pb metal will not react with sodium nitrate (NaNO₃) as sodium remains at the lower position of the activity series than Pb.

Pb + NaNO₃ = No reaction

(b) Pb reacts with HNO₃ to form lead nitrate. The reaction is:

Pb + 4HNO₃ = Pb(NO₃)₂ + 2NO₂ + 2H₂O

(c) The standard reduction potential of Pb²⁺/Pb is more than nickel Ni²⁺/Ni thus there will be no reaction between Pb and NI(NO₃)₂.

Pb + Ni(NO₃)₂ = No reaction.

3. Identification of platinum (Pt)

(a) Pt metal will not react with sodium nitrate (NaNO₃) as sodium remains at the lower position of the activity series than Pt.

Pt + NaNO₃ = No reaction.

(b) The standard reduction potential of Pt²⁺/Pt is so high (+1.188) thus there will be no reaction with HNO₃.

Pt + HNO₃ = No reaction

(c) The standard reduction potential of Pt²⁺/Pt is more than nickel Ni²⁺/Ni thus there will be no reaction between Pt and Ni(NO₃)₂.

Pt +  Ni(NO₃)₂ = No reaction.    

8 0
3 years ago
Please help, its science -&gt;-
WITCHER [35]

Answer:

quantitative

Explanation:

7 0
2 years ago
Balance the following reaction. 2Ca3(PO4)2 + C + 6SiO2 → CaSiO3 + P4 + CO
miskamm [114]

Answer:

2Ca₃(PO₄)₂ + 10C + 6SiO₂ → 6CaSiO₃ + P₄ + 10CO.

Explanation:

  • To balance a chemical reaction, we should apply the law of conservation of mass.

  • Law of conversation of mass states that the no. of atoms is equal in both sides of the chemical reaction.

  • So, the balanced chemical reaction is:

<em>2Ca₃(PO₄)₂ + 10C + 6SiO₂ → 6CaSiO₃ + P₄ + 10CO.</em>

that 2 mol of Ca₃(PO₄)₂ react with 10 mol of C and  6 mol of SiO₂ to produce 6 mol of CaSiO₃, 1 mol of P₄ and 10 mol of CO.

3 0
3 years ago
Read 2 more answers
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