Answer:
4.8 %
Explanation:
We are asked the concentration in % by mass, given the molarity of the solution and its density.
0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:
MW acetic acid = 60.0 g/mol
mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g
mass of solution = 1000 cm³ x 1.010 g/ cm³ (1l= 1000 cm³)
= 1010 g
% (by mass) = 48.00 g/ 1010 g x 100 = 4.8 %
0.05M is the concentration of the solution.
The amount of a chemical substance in a mixture is expressed by the substance's concentration. Concentration can be expressed in numerous ways. In chemistry, the terms "solvent" and "solute" are used to denote the substance of interest and the medium in which it is dissolved, respectively
Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V. To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.
C = m / V
C = 10 / 200
C = 0.05M.
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Below are the choices that can be found from other sources.
The answer is C endothermic and exothermic
<span>a. exothermic and exothermic
b. exothermic and endothermic
c. endothermic and exothermic
d. endothermic and endothermic</span>
The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
The correct answer is A. The boiler
