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3 years ago

Select the correct answer

Mathematics

1 answer:

serg [7]3 years ago

3 0

Answer:

option d is right

Step-by-step explanation:

x2+y2+2ax+2by+a2+b2=-m2

I thinks it's right

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If a triangle has angles that fit the ratio 4:3:2, what would be the measure of each of the angles?

Harman [31]

Answer:

80,60,40

Step-by-step explanation:

The three angles of a triangle add to 180

Multiply the ratio by x

The angles are 4x, 3x, 2x

Add them together

4x+3x+2x = 180

Add like terms

9x = 180

Divide by 9

9x/9 =180/9

x = 20

The angles are 4x = 4(20) = 80

3x= 3(20) = 60

2x= 2(20) = 40

4 0

3 years ago

i need to know how to find the x and y intercepts and then graph the linear equation for the problem x+y=2

gizmo_the_mogwai [7]

Answer:

The x-intercept of the straight line is at (2,0) and the y-intercept is at (0,2).

Join those two points with a straight line and get the graph.

Step-by-step explanation:

The intercept form of a straight line equation is $\frac{x}{a} + \frac{y}{b} = 1$ , where the x-intercept of the line is at (a,0) and the y-intercept will be at (0,b).

So, we have to arrange the equation of a straight line in the intercept form and then we can easily find the x-intercept and y-intercept of the line.

Given equation is x + y = 2

⇒ $\frac{x}{2} + \frac{y}{2} = 1$

Therefore, the x-intercept of the straight line is at (2,0) and the y-intercept is at (0,2).

Now, locate the two points as obtained on the graph and join them with a straight line and you will get the graph of the line. (Answer)

8 0

3 years ago

Saved

nignag [31]

The answer to the question

3 0

4 years ago

Read 2 more answers

Use the method of "undetermined coefficients" to find a particular solution of the differential equation. (The solution found ma

Naddika [18.5K]

Answer:

The particular solution of the differential equation

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

Step-by-step explanation:

Given differential equation y''(x) − 10y'(x) + 61y(x) = −3796 cos(5x) + 185e6x

The differential operator form $(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

<u>Rules for finding particular integral in some special cases:-</u>

let f(D)y = $e^{ax}$ then

the particular integral $\frac{1}{f(D)} (e^{ax} ) = \frac{1}{f(a)} (e^{ax} ) if f(a)$ ≠ 0

let f(D)y = cos (ax ) then

the particular integral $\frac{1}{f(D)} (cosax ) = \frac{1}{f(D^2)} (cosax ) =\frac{cosax}{f(-a^2)}$ f(-a^2) ≠ 0

Given problem

$(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

P<u>articular integral</u>:-

$P.I = \frac{1}{f(D)}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + \frac{1}{D^2-10D+61}185e^{6x})$

P.I = $I_{1} +I_{2}$

we will apply above two conditions, we get

$I_{1}$ =

$\frac{1}{D^2-10D+61}( −3796 cos(5x) = \frac{1}{(-25)-10D+61}( −3796 cos(5x) ( since D^2 = - 5^2)$ $= \frac{1}{(36-10D}( −3796 cos(5x) \\= \frac{1}{(36-10D}X\frac{36+10D}{36+10D} ( −3796 cos(5x)$