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spin [16.1K]
4 years ago
7

On planet X, the absolute pressure at a depth of 2.00 m below the surface of a liquid nitrogen lake is 5.00 × 105 N/m2 . At a de

pth 5.00 m below the surface, the absolute pressure is 8.00 × 105 N/m2 . The density of liquid nitrogen is 808 kg/m3 . a. What is the atmospheric pressure on planet X? b. What is the acceleration due to gravity on planet X?
Physics
1 answer:
eimsori [14]4 years ago
7 0

Answer:

300000.01008 Pa

123.76237 m/s²

Explanation:

\rho = Density of liquid nitrogen = 808 kg/m³

h = Depth

g = Acceleration due to gravity

P = Atmospheric pressure

Absolute Pressure is given by

Below 2 m from surface

P_a=P+\rho gh\\\Rightarrow 5\times 10^5=P+808g\times 2

Below 5 m from surface

P_a=P+\rho gh\\\Rightarrow 8\times 10^5=P+808g\times 5

Subtracting the above equations we get

-3\times 10^5=-808g3\\\Rightarrow g=\frac{3\times 10^5}{808\times 3}\\\Rightarrow g=123.76237\ m/s^2

The acceleration due to gravity on the planet is 123.76237 m/s²

Equating the value of g in the first equation

5\times 10^5=P+808\times 123.76237\times 2\\\Rightarrow P=5\times 10^5-808\times 123.76237\times 2\\\Rightarrow P=300000.01008\ Pa

The atmospheric pressure on the planet is 300000.01008 Pa

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Vitek1552 [10]

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8 0
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Three laws that indicate a chemical change
alexandr1967 [171]

Temperature, The highness, and the time.

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4 0
3 years ago
Modern nuclear bomb tests have created an extra high level of14C in our atmosphere. When future archaeologistsdate samples from
Ipatiy [6.2K]

Answer:

Too old(Ex. if real time is 1000 then they estimate >1000)

Explanation:

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Now nuclear test on planet have significant effect on temperature rise.

Also 14°C rise in temperature is good one because of this.

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Thus too old is right answer.

8 0
3 years ago
If you have two uncertainties, and they are from two different sources and contribute to the uncertainty of a measurement, what
Darya [45]

The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.

                           Δm = ∑  | \frac{dm}{dx_i} | \ \Delta x_i

Physical quantities are precise values ​​of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.

When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the  cases, all the errors add up.

If m is the calculated quantity, x_i the measured values ​​and Δx_i the uncertainty of each value, the total uncertainty is

                      Δm = ∑  | \frac{dm}{dx_i } | \ \Delta x_i    | dm / dx_i | Dx_i

               

for instance:

If the magnitude is  a average of two magnitudes measured each with a different error

                     m = \frac{m_1+m_2}{2}

                     Δm = | \frac{dm}{dx_1} |  Δx₁ + | \frac{dm}{dx_2} | Δx₂

                     \frac{dm}{dx_1} = ½

                     \frac{dm}{dx_2} = ½

                     Δm = \frac{1}{2} Δx₁ + ½ Δx₂

                     Δm = Δx₁ + Δx₂

In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.

Learn more about propagation errors here:

brainly.com/question/17175455

6 0
3 years ago
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