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alex41 [277]
3 years ago
14

The elements selenium and oxygen are both poor electrical conductors. In which section of the periodic table are they

Physics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

The answer to your question is Nonmetals

Explanation:

Nonmetals   they are bad conductors of heat and electricity except graphite.

Metalloids   they are less conductors of electricity than metals.

Noble gases  they conduct electricity.

Halogens they are not metals and do not conduct electricity.

From this information, we conclude that Oxygen and Selenium are nonmetals.

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The Sun's surface temperature is closest to _____.
garik1379 [7]
The answer is b because the sun's surface temperature is 5,778 K.
5 0
3 years ago
Read 2 more answers
How do particles move differently in transverse waves and in surface water waves?
elixir [45]
The particles always move parallel and perpendicular to the waves. The waves which are in the water moves a circle. Both up and down and back and forth.

Good luck :)
3 0
3 years ago
A ski lift carries people along a 220-meter cable up the side of a mountain. Riders are lifted a total of 110 meters in elevatio
jeka94

The ideal mechanical advantage (IMA) can be determined by the following equation:

 IMA= Input distance/Output distance

 The Input distance and Output distance are:

 Input distance=220 meters

 Output distance=110 meters

 When you substitute in the equation of the ideal mechanical advantage (IMA), you obtain:

 IMA= Input distance/Output distance

 IMA= 220 meters/110 meters

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3 0
3 years ago
Consider the power dissipated in a series R–L–C circuit with R=280Ω, L=100mH, C=0.800μF, V=50V, and ω=10500rad/s. The current an
ki77a [65]

Answer:

0.28802

2.57162 W

14.28 W

53.55 W

6.07142 W

Explanation:

R = 280Ω

L = 100 mH

C = 0.800 μF

V = 50 V

ω = 10500rad/s

For RLC circuit impedance is given by

Z=\sqrt{R^2+(X_L-X_C)^2}\\\Rightarrow Z=\sqrt{R^2+(\omega L-\dfrac{1}{\omega C})^2}\\\Rightarrow Z=\sqrt{280^2+(10500\times 100\times 10^{-3}-\dfrac{1}{10500\times 0.8\times 10^{-6}})^2}\\\Rightarrow Z=972.1483\ \Omega

Power factor is given by

F=\dfrac{R}{Z}\\\Rightarrow F=\dfrac{280}{972.1483}\\\Rightarrow F=0.28802

The power factor is 0.28802

The average power to the circuit is given by

P=\dfrac{V^2}{Z}\\\Rightarrow P=\dfrac{50^2}{972.1483}\\\Rightarrow P=2.57162\ W

The average power to the circuit is 2.57162 W

Power to resistor

P_R=IR\\\Rightarrow P_R=5.1\times 10^{-2}\times 280\\\Rightarrow P_R=14.28\ W

Power to resistor is 14.28 W

Power to inductor

P_L=IX_L\\\Rightarrow P_L=5.1\times 10^{-2}\times 10500\times 100\times 10^{-3}\\\Rightarrow P_L=53.55\ W

Power to the inductor is 53.55 W

Power to the capacitor

P_C=IX_C\\\Rightarrow P_C=5.1\times 10^{-2}\times \dfrac{1}{10500\times 0.8\times 10^{-6}}\\\Rightarrow P_C=6.07142\ W

The power to the capacitor is 6.07142 W

8 0
3 years ago
What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?
prohojiy [21]

You've given the answer, right there in your question.

The "magnitude of gravity" is described in terms of the acceleration
due to it, and you just told us what that is.

We can also notice that the figure you gave is about 0.66 of the
acceleration due to gravity on the Earth's surface. That tells us that
the distance from the Earth's center at that height is about 

                     (1 / √0.66) = 1.23 times

the Earth's radius, so the height is about  910 miles above the surface.


7 0
3 years ago
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