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Bond [772]
3 years ago
7

To determine which one of the products in a precipitation reaction is the precipitate, which of the following should you follow?

​
Physics
1 answer:
alexgriva [62]3 years ago
5 0

Answer: Solubility Rules

Explanation: I took it on Ap3x

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n a local coffee shop, a customer slides her empty nitro cold brew downthe counter for a refill. The barista is distracted, and
Marta_Voda [28]

Answer:

5 m/s

Explanation:

Horizontal distance traveled, x = 2 m

vertical distance traveled, y =  4/5 m

Let the speed of cup as it leaves the counter is v and it takes time t to hit the ground.

Use second equation of motion in vertical direction

y = ut+\frac{1}{2}at^{2}

Here acceleration in vertical direction is 9.8 m/s^2.

So,

\frac{4}{5} = 0+\frac{1}{2}\times9.8t^{2}

t = 0.4 second

Now in horizontal direction the acceleration in zero.

Horizontal distance = horizontal velocity x time

x = v t

2 = v (0.4)

v = 5 m/s

Thus, the horizontal velocity of cup as it leaves the counter is 5 m/s.

4 0
3 years ago
What initially unknown quantity, together with the wavelength, is sufficient to calculate the stopping potential for 400 nmnm li
kondaur [170]

Answer:

The initially known quantity, together with the wavelength, that is sufficient to calculate the stopping potential for electrons from the surface of a metal is called the WORK FUNCTION.

Explanation:

The stopping potential is defined as the potential that is required to stop electrons from being ejected from the surface of a metal when light with energy greater than the metal's work function/work potential is incident on the metal.

Given that light is known to be made up of photons, which carry energy in packets according to the frequencies of the light.

The photoelectric phenomenon explains that when light of a certain frequency that corresponds to an energy level that is higher than a metal's work function is incident on a metal, it will lead to electrons being ejected from the surface of the metal. The energy of the ejected electrons is then proportional to the difference between the energy level of the photons and the metal's work function.

Basically, it is the excess energy after overcoming the work function that rejects the electrons.

So, to prevent this excess energy from ejecting electrons from a metal's surface, an energy thay matches this excess must be in place to stop electrons from coming out. This energy/potential required to stop the ejection of electrons, is called the stopping potential.

The stopping potential is given as

eV₀ = hf - ϕ

The stopping potential (eV₀) them depends on the hf and the ϕ.

hf is the energy of the photons, where h is Planck's constant and f is the photons' frequency which is further given as

f = (c/λ)

c = speed of light (speed of the photons)

λ = wavelength of the photons.

The other quantity, ϕ, is the metal's work function; the amount of energy needed to be overcome by the photons before ejection of electrons is possible. It is the minimum energy that the light photoms must possess to even stand a chance of being able to eject electrons from a metal's surface.

So, the stopping potential is the difference between the energy of the photons (obtained using the photons' frequency, wavelength and/or speed) and the metal's work function.

Hope this Helps!!!!

3 0
4 years ago
what is the energy (in eV units) carried by one photon violet light that has a wavelength of 4.5e-7?
DaniilM [7]
The energy of a photon is given by
E=hf
where h is the Planck constant and f is the photon frequency.

We can find the photon's frequency by using the following relationship:
f= \frac{c}{\lambda}
where c is the speed of light and \lambda is the photon's wavelength. By plugging numbers into the equation, we find
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.67 \cdot 10^{14}Hz

And so now we can find the photon energy
E=hf=(6.6 \cdot 10^{-34} Js)(6.67 \cdot 10^{14}Hz )=4.4 \cdot 10^{-19} J

We know that 1 Joule corresponds to
1 J = 1.6 \cdot 10^{-19} eV
So we can convert the photon's energy into electronvolts:
E= \frac{4.4 \cdot 10^{-19} J }{1.6 \cdot 10^{-19} J/eV}=2.75 eV
4 0
4 years ago
Which type of wave is classified as electromagnetic?
Nimfa-mama [501]

Answer: B) Light

Explanation: light waves are Electromagnetic waves. Visible light is one of the many types of electromagnetic waves. The others are mechanical waves.

8 0
3 years ago
Read 2 more answers
Which wave has the greatest amplitude?
pychu [463]

It is the red line the purple line carries the most the green line is the largest and the smallest is sky blue

4 0
4 years ago
Read 2 more answers
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