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sladkih [1.3K]
3 years ago
14

Jules is conducting an experiment involving friction. He is measuring the temperature of various objects and surfaces after quic

kly rubbing them together.
He is testing a steel ball bearing and a tennis ball on carpet, linoleum flooring, and a glass surface by rubbing the object 20 times in 6 seconds over the surface.
Match the predictions based on the most likely result of his experiment
correct prediction -


incorrect prediction -


The tennis ball over the linoleum floor will have no friction, as the temperatures will not change.

The temperature of the surface of the ball bearing when rubbed over glass will be the least.
Physics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

The correct prediction will be:  

The temperature of the surface of the ball bearing when rubbed over glass will be the least.

The incorrect prediction:

The tennis ball over the linoleum floor will have no friction, as the temperatures will not change.

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Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
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Answer:

inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

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Balanced forces acting on an object cause the object to accelerate. Please select the best answer from the choices provided T F
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3 years ago
n the Bohr model of the hydrogen atom (see Section 39.3), in the lowest energy state the electron orbits the proton at a speed o
Ivahew [28]

Answer:

(a) T=1.5*10^{-6}s

(b) I=1.1*10^{-3}A

(c) \mu=9.71*10^{-24}A\cdot m^2

Explanation:

(a) The orbital period is the time that the electron spend to travel the orbit of the atom. Thus, it is given by the length of the circular orbit divided by its velocity:

T=\frac{2\pi r}{v}\\T=\frac{2\pi(5.3*10^{-11}m)}{2.2*10^{6}\frac{m}{s}}\\T=1.5*10^{-6}s

(b) Current means charge over time, So, in this case is charge over period:

I=\frac{q}{t}\\I=\frac{e}{T}\\I=\frac{1.6*10^{-19}C}{1.5*10^{-6}s}\\\\I=1.1*10^{-3}A

(c) Magnetic moment is given by:

\mu=IA

Here A is the area of the orbit.

\mu=I\pi r^2\\\mu=(1.1*10^{-3}A)\pi(5.3*10^{-11}m)^2\\\mu=9.71*10^{-24}A\cdot m^2

4 0
3 years ago
The SAME amount of current I passes through three different resistors. R2 has twice the cross-sectional area and the same length
Snezhnost [94]

Answer:

resistor R₂ has the lowest current density

Explanation:

The current density is

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now let's analyze each case

a) R₂ has an area 2A₀ and a length L₀ that R₁

b) R₃ has an area Ao and a length 3L₀ what R₁

we can see that all the area is given in relation to the resistance R₁

 

the current density in R₁ is

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the current density in R₂

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the current density in R₃

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         j₂ < j₁ = j₃

therefore resistor R₂ has the lowest current density

5 0
3 years ago
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