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Snezhnost [94]
3 years ago
7

Our goal is to design a traffic-light controller with the following properties; it lights up the green light (output G) for 15 s

econds, followed by the yellow light (output Y) for 9 seconds, then the red light (output R) for 12 seconds. The controller will repeat this pattern forever. Our system will have a clock signal with a period of 3 seconds. 1. How many states, N, are needed in a FSM to implement this controller
Engineering
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

There will be three (3) states that will be needed in-order to implement the FSM controller.

Explanation:

FSM stands for  Finite-State Machine. This is an example of a model used in  mathematical computation. The FSM is an abstract machine that can be in exactly one of a finite number of states at any given time.

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Choose the statement that correctly describes the circuit below. image is not found a. The above circuit is invalid because nMOS
OleMash [197]

The statement that correctly describes the circuit is the circuit provided is an example of a CMOS circuit.

<h3>What is a CMOS circuit?</h3>

The CMOS circuit is a term that is often known as "Complementary Metal Oxide Semiconductor."

This is known to be a machine that create integrated circuits and it is one that is often seen a a lot of electronic component and as such, the the circuit provided is an example of a CMOS circuit.

Learn more about circuit  from

brainly.com/question/2969220

#SPJ1

8 0
2 years ago
What are the two types of furnaces used in steel production?
Kobotan [32]

Explanation:

The two types of furnaces used in steel production are:

<u>Basic oxygen furnace </u>

In basic oxygen furnace, iron is combined with the varying amounts of the steel scrap and also small amounts of the flux in the Blast Furnace. Lance is introduced in vessel and blows about 99% of the pure oxygen causing rise in temperature to about 1700°C. This temperature melts scrap and the impurities are oxidized and results in the liquid steel.

<u>Electric arc furnace</u>

Electric arc furnace reuses existing steel. Furnace is charged with the steel scrap. It operates on basis of electrical charge between the two electrodes providing heat for process. Power is supplied through electrodes placed in furnace, which produce arc of the electricity through scrap steel which raises temperature to about 1600˚C. This temperature melts scrap and the impurities can be removed through use of the fluxes and results in the liquid steel.

3 0
3 years ago
The fan pressure differential gage on an air handler reads 12 cm H2O. What is this pressure differential in kiloPascals
Deffense [45]

Answer:

1.18\ \text{kPa}

Explanation:

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

h = Height of reading = 12 cm

\rho = Density of water = 1000\ \text{kg/m}^3

Pressure due to height difference is given by

P=\rho gh\\\Rightarrow P=1000\times 9.81\times 12\times 10^{-2}\\\Rightarrow P=1177.2\ \text{Pa}=1.1772\ \text{kPa}\approx 1.18\ \text{kPa}

The pressure differential is 1.18\ \text{kPa}.

4 0
3 years ago
Strong performance in your engineering discipline ordinarily is one necessary condition for becoming a successful engineering ma
zhenek [66]

Answer:

1.  Manpower Management

2. Productive Meetings

3.Establish administrative policies, procedures, and standards.

4. High command over assets management.

5. Specific field related knowledge of procurement.

6. Compliance and EHS  knowledge.

Explanation:

4 0
3 years ago
An air-conditioning system is used to maintain a house at 70^\circ{} ∘ F when the temperature outside is 100^\circ{} ∘ F. The ho
Vika [28.1K]

Answer:

the minimum power input required for this air-conditioning system is 1.20 hp

Explanation:

Given the data in the question;

Temperature inside ( Sink ) T_L = 70°F = ( 70 + 460 )R = 530 R

temperature outside ( source )T_H = 100°F = ( 100 + 460 )R = 560 R

Q_W = 800 Btu/min

Q_L = 100  Btu/min

Now, from the equation of coefficient of performance of refrigerator;

COP_{Ref = Desired output / Required input

COP_{Ref = Q_{out / W_{net --------- let this be equation 1

COP_{Ref = ( Q_L + Q_W ) / W_{net

where Q_W is the rate heat gained through the wall

Q_L is the heat generation from people and lights and appliances.

Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;

COP_{Ref = T_L / ( T_H - T_L )

we substitute

COP_{Ref = 530 / ( 560 - 530 )

COP_{Ref = 530 / 30

COP_{Ref = 17.667

so we substitute into equation 1;

COP_{Ref = Q_{out / W_{net ---------

COP_{Ref = ( Q_L + Q_W ) / W_{net

17.667 = ( 100 + 800 ) / W_{net

17.667 = 900 / W_{net

W_{net = 900 / 17.667

W_{net = 50.94 Btu/min

W_{net = ( 50.94 / 42.53 ) hp

W_{net = 1.198 hp ≈ 1.20 hp

Therefore, the minimum power input required for this air-conditioning system is 1.20 hp

5 0
3 years ago
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