Answer:
vehicle density = 28.205 veh/mile
flow rate = 0.909 veh/hr
Explanation:
given data
count n = 21
distance = 0.78 miles
speed = 52 mph
solution
we get here vehicle density that is express as
vehicle density = n ÷ distance ...............1
vehicle density = ( 21 + 1 ) ÷ 0.78
vehicle density k = 28.205 veh/mile
and
now we get here flow rate that is express as
flow rate = k × vs .................2
flow rate = 28.205 × ( 52 × 0.00062 ÷ 1m )
flow rate = 0.909 veh/hr
Answer:0.3166N
Explanation:
Given data
Area 
Gap below top plate
Gap above bottom plate
SAE 30 oil viscosity =
Velocity of middle plate
There will viscous force on middle plate i.e. at above surface and below surface
Viscous force
![Net Force on plate F =\mu Av\left [\frac{1}{y_1} +\frac{1}{y_2}\right ]](https://tex.z-dn.net/?f=Net%20Force%20on%20plate%20F%20%3D%5Cmu%20Av%5Cleft%20%5B%5Cfrac%7B1%7D%7By_1%7D%20%2B%5Cfrac%7B1%7D%7By_2%7D%5Cright%20%5D)
![F=0.38\times 500\times 10^{-4}\left [\frac{1}{20\times 10^{-3}} +\frac{1}{30\times 10^{-3}}\right ]](https://tex.z-dn.net/?f=F%3D0.38%5Ctimes%20500%5Ctimes%2010%5E%7B-4%7D%5Cleft%20%5B%5Cfrac%7B1%7D%7B20%5Ctimes%2010%5E%7B-3%7D%7D%20%2B%5Cfrac%7B1%7D%7B30%5Ctimes%2010%5E%7B-3%7D%7D%5Cright%20%5D)

this is force by oil on plate thus we need to apply atleast 0.3166N to move plate
The Travel Speed at which the welding operation can be accomplished is given as 7.147mm/s. See the computation below.
<h3>What is travel speed?</h3>
The travel speed of the welding flame or gun across the workpiece is simply measured in millimeters per minute.
Travel speed, along with voltage and amperage, is one of three factors in arc welding that affect the amount of heat input.
<h3>What is the calculation that justifies the above answer is?</h3>
We are given the following:
Melting temperature = 1650 K
k = (3.33 * 10⁻⁶) * (1,650)²
k = 9.066 J/mm^3
The formula for velocity here is given as:
V = f1 * f2 * Rh / (k*A)
V = 0.9 * 0.6 * 3000 / (9.066*25)
V = 7.147 mm/s
Hence, the Travel Speed at which the welding operation can be accomplished is given as 7.147mm/s.
Learn more about welding operation at;
brainly.com/question/22494632
#SPJ1
Answer:
This is not a clear indication of the hot zone as the information of the radioactivity of the background is not provided clearly.
Explanation:
According to IAEA as well as NRCP, the hot area is defined on the basis of the radioactivity reading it shows instead of contrast or comparative reading from the background. The value of radiation activity which will be required to declare an area as hot zone is if it is greater than 0.1 mSv/h or
.
Answer:
The correct answer to the following question will be "
or
".
Explanation:
- Since along that same z-axis none electromagnetic field would be triggered as being in the same orientation loop movement of them across different line portions would allow some caused emf/voltage to be canceled. And the only logical choice seems to be either x or y-axes.
- The magnetic field of fluctuation should indeed be changed and changed across both X as well as Y directions.
So that the above is the appropriate choice.