A plane, opaque, surface M has the following properties: gray, diffuse, absorptivity = 0.7, surface area = 0.5 m2 , temperature
1 answer:
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Answer:
11.541 mol/min
Explanation:
temperature = 35°C
Total pressure = 1.5 * 1.013 * 10^5 = 151.95 kPa
note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )
from steam table it is = 5.6291 Kpa
calculate the mole fraction of H ( YH
)
= 5.6291 / 151.95
= 0.03704
calculate the mole fraction of air ( Yair )
= 1 - mole fraction of water
= 1 - 0.03704 = 0.9629
Now to determine the molar flow rate of water vapor in the stream
lets assume N = Total molar flow rate
NH = molar flow rate of water
Nair = molar flow rate of air = 300 moles /min
note : Yair * n = Nair
therefore n = 300 / 0.9629 = 311.541 moles /min
Molar flowrate of water
= n - Nair
= 311.541 - 300 = 11.541 mol/min
Answer:
Code is given as below:
Explanation:
#include <iostream>
using namespace std;
//function prototype declaration
void MilitaryTime(int, int, char, int &, int &);
int main()
{
//declare required variables
int SHour, SMin, MHour, MMin;
char AorP;
//promt and read the hours from the user
cout<<"Enter hours in standard time : ";
cin>>SHour;
//check the hours are valid are not
while(SHour<0 || SHour>12)
{
cout<<"Invalid hours for standard time. "
<<"Try again..."<<endl;
cout<<"Enter hours in standard time : ";
cin>>SHour;
}
//promt and read the minutes from the user
cout<<"Enter minutes in standard time : ";
cin>>SMin;
//check the minutes are valid are not
while(SMin<0 || SMin>59)
{
cout<<"Invalid minutes for standard time. "
<<"Try again..."<<endl;
cout<<"Enter minutes in standard time : ";
cin>>SMin;
}
//promt and read the am or pm from the user
cout<<"Enter standard time meridiem (a for AM p for PM): ";
cin>>AorP;
//check the meridiem is valid are not
while(!(AorP=='a' || AorP=='p' || AorP=='A' || AorP=='P'))
{
cout<<"Invalid meridiem for standard time. "
<<"Try again..."<<endl;
cout<<"Enter standard time meridiem (a for AM p for PM): ";
cin>>AorP;
}
//call function to calculate the military time
MilitaryTime(SHour, SMin, AorP, MHour, MMin);
//fill zeros and display standard time
cout.width(2);
cout.fill('0');
cout<<SHour<<":";
cout.width(2);
cout.fill('0');
cout<<SMin;
if(AorP=='a' || AorP=='A')
cout<<" am = ";
else
cout<<" pm = ";
//fill zeros and display military time
cout.width(2);
cout.fill('0');
cout<<MHour;
cout.width(2);
cout.fill('0');
cout<<MMin<<endl;
system("PAUSE");
return 0;
}
//function to calculate the military time with reference parameters
void MilitaryTime(int SHour, int SMin, char AorP, int &MHour, int &MMin)
{
//check the meredium is am or pm
//and calculate hours
if(AorP=='a' || AorP=='A')
{
if(SHour==12)
MHour = 0;
else
MHour = SHour;
}
else
MHour = SHour+12;
MMin = SMin;
