Answer:
Explanation:
Given that:
f = 250 Hz
= 2%
= 600 Hz
= 0.5 to 1.5 increment by 0.05
For 250 Hz = 250 cycle/sec
M = 0.98 , 1.02
At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M
At 0.6330 value of damping ratio the error value was 2% at 1.02 value of M.
Hence, the damping ratio of the transducer must be placed between 0.6330 to 0.7183
1.25, because change the fractions into decimals and then add it from there so it would be add like, 0.75+0.5=1.25
Answer:
import java.util.Scanner;
public class CountByAnything
{
public static void main (String args[])
{
int beginning = 5;
int ending = 200;
Scanner s = new Scanner(System.in);
System.out.println("Enter the value to count by:");
int valueToCount = s.nextInt();
int counter = 0;
for(int i = beginning; i <= ending; i += valueToCount)
{
System.out.print(i + " ");
if((counter+1) % 10 == 0)
System.out.println();
counter++;
}
}
}
Explanation:
- Initialize the beginning and ending.
- Loop through the value of ending variable.
- Check if numbers per line is equal to ten and Increment the counter
.
Answer:
Explanation:
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Answer:
B. energy an object has because of its motion or position
Explanation: