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Elina [12.6K]
2 years ago
7

Name the four ways in which heat is transferred from a diesel engine

Engineering
1 answer:
NeTakaya2 years ago
3 0

Answer:

hope this helps!

Explanation:

Download pdf
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For a short time a rocket travels up and to the left at a constant speed of v = 650 m/s along the parabolic path y=600−35x2m, wh
julia-pushkina [17]

Answer:

Detailed working is shown

Explanation:

The attached file shows a detailed step by step calculation..

4 0
3 years ago
A smooth sphere with a diameter of 6 inches and a density of 493 lbm/ft^3 falls at terminal speed through sea water (S.G.=1.0027
Pachacha [2.7K]

Given:

diameter of sphere, d = 6 inches

radius of sphere, r = \frac{d}{2} = 3 inches

density,  \rho} = 493 lbm/ ft^{3}

S.G = 1.0027

g = 9.8 m/ m^{2} = 386.22 inch/ s^{2}

Solution:

Using the formula for terminal velocity,

v_{T} = \sqrt{\frac{2V\rho  g}{A \rho C_{d}}}              (1)

(Since, m = V\times \rho)

where,

V = volume of sphere

C_{d} = drag coefficient

Now,

Surface area of sphere, A = 4\pi r^{2}

Volume of sphere, V = \frac{4}{3} \pi r^{3}

Using the above formulae in eqn (1):

v_{T} = \sqrt{\frac{2\times \frac{4}{3} \pir^{3}\rho  g}{4\pi r^{2} \rho C_{d}}}

v_{T} = \sqrt{\frac{2gr}{3C_{d}}}  

v_{T} = \sqrt{\frac{2\times 386.22\times 3}{3C_{d}}}

Therefore, terminal velcity is given by:

v_{T} = \frac{27.79}{\sqrt{C_d}} inch/sec

3 0
3 years ago
If it took 2 hours to clean 4 houses how many houses could be cleaned in 3 hours
Lena [83]

Answer:

6 houses

Explanation:

because

2hrs=4 houses which means you are cleaning 2houses in one hour

so in 3 hours you will houses because you will clean 2 houses in one hour

I hope this helped you sorry if I am wrong

6 0
3 years ago
) A brick of clay is being dried in a batch dryer using constant drying conditions. You have been asked to determine the amount
dimaraw [331]

Answer:

The drying time is calculated as shown

Explanation:

Data:

Let the moisture content be = 0.6

the free moisture content be = 0.08

total moisture of the clay  = 0.64

total drying time for the period = 8 hrs

then if the final dry and wet masses are calculated, it follows that

t = (X0+ Xc)/Rc) + (Xc/Rc)* ln (Xc/X)

 = 31.3 min.

4 0
3 years ago
The rate of heat transfer between a certain electric motor and its surroundings varies with time as , Q with dot on top equals n
tekilochka [14]

Answer:

the required expression is E_2 - E_1 = 4[ 1 - e^{(-0.05t)} ]

Explanation:

Given the data in the question;

Q = -0.2[ 1 - e^(-0.05t) ]

ω = 100 rad/s

Torque T = 18 N-m

Electric power input = 2.0 kW

now, form the first law of thermodynamics;

dE/dt = dQ/dt + dw/dt = Q' + w'

dE/dt = Q' + w'  ------ let this be equation 1

w' is the net power on the system

w' = w_{elect - w_{shaft

w_{shaft = T × ω

we substitute

w_{shaft= 18 × 100

w_{shaft = 1800 W

w_{shaft = 1.8 kW  

so

w' = w_{elect - w_{shaft

w' = 2.0 kW - 1.8 kW

w' = 0.2 kW

hence, from equation 1, dE/dt = Q' + w'

we substitute

dE/dt = -0.2[ 1 - e^{(-0.05t) ] + 0.2

dE/dt = -0.2 + 0.2e^{(-0.05t) ] + 0.2

dE/dt = 0.2e^{(-0.05t)

Now, the change in total energy, increment E, as a function of time;

ΔE = \int\limits^t_0}\frac{dE}{dt}  . dt

ΔE = \int\limits^t_0} 0.2e^{(-0.05t)} dt

ΔE = \int\limits^t_0} \frac{0.2}{-0.05} [e^{(-0.05t)}]^t_0

E_2 - E_1 = 4[ 1 - e^{(-0.05t)} ]

Therefore, the required expression is E_2 - E_1 = 4[ 1 - e^{(-0.05t)} ]

5 0
2 years ago
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