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2 years ago

13

There are 6 minutes of commercials for every 24 minutes of television how many minutes of commercials are there in 1 hour and 36

minutes of televisions.?

1 answer:

topjm [15]2 years ago

8 0

I think it is 16, I hope this helped

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Expand (x-2)^7 using binomial theorem

umka2103 [35]

Answer:

Urr answer...

Step-by-step explanation:

<h3 /><h3 /><h3 /><h3 /><h3>i hope its help to you ✌</h3>

4 0

1 year ago

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Look at the sequence 15 3 0.6 0.12 what is the next number in the sequence

spayn [35]

0.024

You’re dividing by 5 each time

3 0

2 years ago

The formula that relates the length of a ladder, L, that leans against a wall with distance d from the base of the wall and the

anygoal [31]

Answer:

<u>The correct answer is C. 14.6 feet</u>

Step-by-step explanation:

Information given to solve the case:

Length of the ladder = 15 feet

Distance from the base of the wall = 3.5 feet

Using the Pythagorean theorem for finding the height, because this is a right triangle:

h² = Length of the ladder ² - Distance from the base of the wall ²

h² = 15 ² - 3.5 ²

h² = 225 - 12.25

h² = 212.75

h = √ 212.75

h = 14.59

<u>h = 14.6 feet (Rounding to one decimal place)</u>

4 0

2 years ago

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Find the circumference of the circle if the square has an area of 144 m2. Give your answer to the nearest tenth. Use 3.14 form

Paladinen [302]

Circumference of Circle = 2πr
Area of circle = πr²
144 = 3.14 * r²
r² = 144/3.14
r² = 45.85
r = √45.85
r = 6.77

Circumference = 2πr = 2*3.14*6.77
Circumference = 42.51 m²

So, your answer is 42.51 m²

6 0

2 years ago

The cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 10 units, and

Ilia_Sergeevich [38]

Answer:

The volume of the cylinder is 2.1 times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the pyramid

we know that

The volume of a right pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base of pyramid

H is the height of the pyramid

we have

$H=10\ units$

substitute

$Vp=\frac{10}{3}B\ units^{3}$

step 2

Find the volume of the right cylinder

we know that

The volume of right cylinder is equal to

$V=BH$

where

B is the area of the base of cylinder

H is the height of the cylinder

we have

$H=7\ units$

substitute

$Vc=7B\ units^{3}$

step 3

Compare the volumes

we know that

The area of the base both figures are congruent

Find the ratio of their volumes

$\frac{Vp}{Vc}$

substitute

$\frac{Vp}{Vc}=\frac{(\frac{10}{3}B)}{7B}$

Simplify

$\frac{Vp}{Vc}=\frac{10}{21}$

$21Vp=10Vc\\\\Vc=2.1Vp$

therefore

The volume of the cylinder is 2.1 times the volume of the pyramid

7 0

2 years ago

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