One-eighth of an original radioactive sample will remain at the end of __________ half-lives.
1 answer:
You might be interested in
Answer:
Explanation:
As we know the , equation of time period for simple pendulum ,
T = 2*pi*
hence putting values we get ,
the solution is in picture ,
please
Brain-list it or support me at my U-Tube channel " ZK SOFT&GAMING " I will be thankful
Answer: a) 1 b) 61 W c) 61 W
Explanation:
a) The Power Factor (also known as cos φ), is defined by the difference in phase between current and voltage, in a RLC series circuit, and is expressed as follows:
cos φ = R / Z = R /
In resonance, XL =XC, so the circuit behaves like it were purely resistive, so Z=R.
Replacing in the expression for power factor, we have:
cos φ = R/Z = R/R = 1
This means that in resonance, current and voltage are in phase each other.
b) The average power delivered by the source, in resonance, is simply the power dissipated at the resistance R, as follows:
Pavg = V² rms / R = V₀² / √2 / R = 61 W
c) If the circuit remains in resonance, the average power , which does not depends on frequency provided this condition remains, keeps the same, i.e. , 61 W.