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polet [3.4K]
3 years ago
15

If a water wave vibrates up and down three times each second and the distance between wave crests is 2 meters, what are:

Physics
2 answers:
finlep [7]3 years ago
4 0

a). 3 Hz

b). 2 meters

c). 6 m/s

Helga [31]3 years ago
3 0

Answer:

im here for help

Explanation:

help

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a woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minu
TiliK225 [7]

When a  woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minutes. then the woman's average speed during her entire motion would be  73.15 meters /minute.

<h3>What is speed?</h3>

The total distance covered by any object per unit of time is known as speed.

the mathematical expression for speed is given by

speed = total; distance /total time

As given in the problem a woman walks south at a speed of 2.0mph for 60 minutes

60 min = 1 hour

1 mile = 1.60934 km

The distance covered by her southwards  =  speed ×time

                                                                      =2 mph × 60 minutes

                                                                      = 3.218 km

She then turns around and walks north at a distance of 3000m in 25 minutes

The distance covered northward is 3000m

speed = total distance /total time

          =(3218 +3000) /(60+25)

          =73.15 meters /minutes

Thus, The average speed of the woman would be 73.15 meters /minute.

Learn more about speed from here

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8 0
1 year ago
Can someone love me pls
dlinn [17]

that's sad that you are trying to find love on this app :(

6 0
3 years ago
A capacitor is charged to 8.0×10−4 C , then discharged by connecting a wire between the two plates. 35us after the discharge beg
Anettt [7]

Answer:

The average current is 19.567 A

Solution:

As per the question:

Charge, Q = 8.0\times 10^{- 4}\ C

Time, t = 35\times 10^{- 6}\ s

Now,

We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:

I = \frac{Q}{t}                 (1)

Now, the charge that was transferred is 86 % of the original value.

Therefore,

We replace Q by 0.86Q in eqn (1):

I = \frac{0.86\times 8.0\times 10^{- 4}}{35\times 10^{- 6}} = 19.657\ A

7 0
3 years ago
An aminoacyl-trna that enters the a site of the ribosome will next occupy which site?
kkurt [141]

Answer:

The P site

Explanation:

After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.

In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.

5 0
3 years ago
Sir Dudley the Dextrous is loading cannons on top of the castle's tallest towers in preparation for an expected attack. He slips
JulsSmile [24]

Answer:

6667.9 J

Explanation:

We are given that

Mass of cannon.m=14 kg

Time,t=3.15 s

Initial velocity,u=0

We have to find the work done by gravity on the falling cannon ball.

g=9.8 m/s^2

h=ut+\frac{1}{2}gt^2

Substitute the values

h=0+\frac{1}{2}\times 9.8\times (3.15)^2=48.6 m

Work done,W=mgh

Using the formula

W=14\times 9.8\times 48.6=6667.9 J

4 0
3 years ago
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