When a woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minutes. then the woman's average speed during her entire motion would be 73.15 meters /minute.
<h3>What is speed?</h3>
The total distance covered by any object per unit of time is known as speed.
the mathematical expression for speed is given by
speed = total; distance /total time
As given in the problem a woman walks south at a speed of 2.0mph for 60 minutes
60 min = 1 hour
1 mile = 1.60934 km
The distance covered by her southwards = speed ×time
=2 mph × 60 minutes
= 3.218 km
She then turns around and walks north at a distance of 3000m in 25 minutes
The distance covered northward is 3000m
speed = total distance /total time
=(3218 +3000) /(60+25)
=73.15 meters /minutes
Thus, The average speed of the woman would be 73.15 meters /minute.
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Answer:
The average current is 19.567 A
Solution:
As per the question:
Charge, Q = 
Time, t = 
Now,
We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:
I = 
(1)
Now, the charge that was transferred is 86 % of the original value.
Therefore,
We replace Q by 0.86Q in eqn (1):
I = 
Answer:
The P site
Explanation:
After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.
In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.
Answer:
6667.9 J
Explanation:
We are given that
Mass of cannon.m=14 kg
Time,t=3.15 s
Initial velocity,u=0
We have to find the work done by gravity on the falling cannon ball.
Substitute the values
Work done,W=mgh
Using the formula
