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This question can be solved using the concept of friction energy.
The thermal energy change is b "258.4 J".
The change in thermal energy will be equal to the friction energy produced during the motion of the box.
where,
μ = coefficient of kinetic friction = 0.4
f = force applied = 38 N
d = distance traveled by the box = 17 m
Therefore,
<u>E = 258.4 J</u>
Learn more about friction energy here:
Answer:
0.166 rad/s
Explanation:
See attachment for calculations
Answer:
Explanation:
Given that:
Charge (q) on the particle = 3 × 10⁻⁸ C
mass (m) of the particle = 6 × 10⁻⁹ kg
at a distance x = 15 cm , the velocity in the plate = 900 m/s²
For the square plate, the surface charged density σ = -8 × 10⁻⁶ C/m²
To start with calculating the electric field as a result of the square plate; we use the formula;
On the square plate; The electric force F = Eq
The acceleration
For the particle, the velocity at distance x = 7 m can be calculated by using the formula:
From the calculation, we realize that the charge acting between the particle and the plate is said to be "opposite".
Hence, the force is an attractive force.
Similarly, there is a gradual increase exhibited by the velocity of the particle.
Therefore, the particles get to the detector, but the detector failed to get detect due to the velocity which is greater than 1000 m/s.