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amm1812
3 years ago
6

R o b l o x is down today

Physics
1 answer:
madam [21]3 years ago
6 0
nobody cares play a better game
You might be interested in
A square 1300-turn coil with the area of 0.2 m2 is situated in the xy-plane in a region where the magnetic field is (50k) μT. Wh
givi [52]

Answer:

e = 65 mA

Explanation:

given,

number of turn = 1300

Area = 0.2 m²

B = 50 x 10⁻⁶T

t = 0.2 s

coil rotate in x-z plane

θ = 90°  to θ = 0°

maximum induced emf

e = -\dfrac{BAn(cos \theta_f - cos\theta_i)}{\Delta t}

e = -\dfrac{1300 \times 0.2 \times 50\times 10^{-6}(cos 90^0- cos0^0)}{0.2}

e =0.065

e = 65 mA

7 0
4 years ago
What does Pangaea mean?
Rainbow [258]
Pangaea refers to All Land
7 0
4 years ago
Read 2 more answers
A train rolls past a stationary observer. To him, the train is moving at a speed of 23m/s west, and a woman on the train is movi
GREYUIT [131]

Answer:

21.7 seconds.

Explanation:

Woman's velocity relative to train (23 m/s - 22.4 m/s) = 0.6 m/s

Distance woman wants to travel = 13m

To find how long she will take to move 13m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.

(13m)/(0.6 m/s) = 21.6667 seconds or 21.7 seconds.  

Therefore, it will take the woman 21.7 seconds to move 13m.

4 0
3 years ago
A wave that can travel only through what is a mechanical wave
WINSTONCH [101]
The answer is matter
6 0
3 years ago
  After giving an intense performance, a confused and disoriented flautist has wandered onto the motorway! They are playing a con
leva [86]
This is a Doppler effect. Generally, if you move to a frequency source, you would detect an increase in frequency and when you move away from a source you would detect a decrease.

For this question, before you pass them, you are actually approaching them, so you would hear a higher frequency than the constant 300 Hz they are playing at.

Using the condensed formula:

 f '   =   ((v <u>+</u> vd)/(v <u>+</u> vs)) * f

Where:  vd = Velocity of the detector.
              vs = Velocity of the frequency source.
              v   =  Velocity of sound in air.
              f '  =  Apparent frequency.
              f    =  Frequency of source.

v = 343 m/s,  vd = detector = 27.8 m/s,  vs = velocity of the source =0. (the flautists are not moving).
f = 300 Hz. 

There would be an overall increase in frequency, so we maintain a plus at the numerator and a minus at the denominator.

 f '   =   ((v + vd)/(v - vs)) * f

f '   =   ((343+ 27.8)/(343 - 0)) * 300
      =   (370.8/343)* 300 =  324.3

Therefore frequency before passing them = 324.3 Hz.

Cheers.
4 0
3 years ago
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