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alina1380 [7]
3 years ago
6

Reduce Reflects Transfers Stops

Physics
1 answer:
Bond [772]3 years ago
4 0
I think transfers is the answer
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Find the weight of a 2000 kg elaphant
Vika [28.1K]

19,600 Newtons (about 4,400 pounds).

On Earth only.

Different in other places.

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3 years ago
A car moves from rest condition moves with acceleration 4 ms^-2.After 5s,calculate velocity of the car and the distance traveled
lisov135 [29]

Answer:

1) 20 m/s

2) 60 meters

Explanation:

with a constant acceleration of 4m/s/s, the vehicle will end up traveling at 20 m/s after 5 seconds, and will have travelled 60 meters.

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4 years ago
Relate the structure of water to its ability to act as a solvent
pishuonlain [190]

Explanation:

Water (H2O) as a polar covalent molecule has its arrangement of oxygen and hydrogen atoms where one end (hydrogen) has a partially positive charge while the other side (oxygen) had a partially negative charge.

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What change takes place in a wave when the frequency of the wave increases?
Musya8 [376]
The answer is C. As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.
4 0
3 years ago
Estimate how long it would take one person to mow a football field using an ordinary home lawn mower. Assume the mower moves wit
bekas [8.4K]

Answer:

t = 11.9 h = 0.49 day

Explanation:

First of all, we will find the area covered by the mower per unit time:

Rate\ of\ Area\ Covered\ by\ Mower = vw

where,

v = speed of mower = 1 km/h = 1000 m/h

w = width of mower = 0.6 m

Therefore,

Rate\ of\ Area\ Covered\ by\ Mower = (1000\ m/h)(0.6\ m)\\Rate\ of\ Area\ Covered\ by\ Mower = 600\ m^{2}/h

Now, the standard football ground has an area of:

A = 105 m x 68 m = 7140 m²

Therefore, The time required to mow the lawn will be:

Time\ to\ Mow\ the\ Lawn = t = \frac{A}{Rate\ of\ Area\ Covered\ by\ Mower}\\t = \frac{7140\ m^{2}}{600\ m^{2}/h}

<u>t = 11.9 h = 0.49 day</u>

8 0
3 years ago
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