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pishuonlain [190]
3 years ago
13

Didifference between uniform and variable velocity ​

Physics
2 answers:
Nat2105 [25]3 years ago
4 0

ᴜɴɪꜰᴏʀᴍ ᴠᴇʟᴏᴄɪᴛy ᴅᴏᴇꜱ'ɴᴛ ᴄʜᴀɴɢᴇ ᴡɪᴛʜ ᴛɪᴍᴇ , ᴡʜɪʟᴇ ᴠᴀʀɪᴀʙʟᴇ ᴠᴇʟᴏᴄɪᴛy ᴄʜᴀɴɢᴇꜱ ᴡɪᴛʜ ʀᴇꜱᴩᴇᴄᴛ ᴛᴏ ᴛɪᴍᴇ . ᴠᴇʟᴏᴄɪᴛy ɪꜱ ᴅᴇꜰɪɴᴇᴅ ᴀꜱ ᴛʜᴇ ᴄʜᴀɴɢᴇ ɪɴ ᴩᴏꜱɪᴛɪᴏɴ ᴏꜰ ᴀ ʙᴏᴅy ɪɴ ᴏɴᴇ ᴜɴɪᴛ ᴏꜰ ᴛɪᴍᴇ ᴏʀ ᴛʜᴇ ᴅɪꜱᴩʟᴀᴄᴇᴍᴇɴᴛ ᴏꜰ ᴛʜᴇ ʙᴏᴅy ɪɴ ᴏɴᴇ ᴜɴɪᴛ ᴏꜰ ᴛɪᴍᴇ .

ꜱɪɴᴄᴇ ᴠᴇʟᴏᴄɪᴛy ᴄʜᴀɴɢᴇꜱ ɪᴛꜱ ᴩᴏꜱɪᴛɪᴏɴ ɪɴ ᴏɴᴇ ᴜɴɪᴛ ᴏꜰ ᴛɪᴍᴇ , ɪᴛ ʜᴀꜱ ᴀ ꜱᴩᴇᴄɪꜰɪᴄ ᴅɪʀᴇᴄᴛɪᴏɴ.

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ yᴏᴜ !!

Simora [160]3 years ago
3 0

Answer:

Uniform velocity is scalar , while variable velocity is vector

Explanation: Uniform velocity and variable velocity is that a body moving with uniform velocity has zero acceleration, while a body that is moving with variable velocity has some acceleration. Uniform velocity is the vector quantity while non-uniform or variable velocity is a scalar quantity

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Design a voltage divider to provide the following approximate voltages with respect to ground using a 30 V source: 8.18 V, 14.7
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Answer:

R₁ = 14.7 10³ Ω , R₂ = 8.18 10³ Ω ,  R₃ = 1.72 10³ Ω ,  R₄ = 5.4 10³ Ω    1/8 W resistor

Explanation:

For this exercise we must use a series circuit since the sum of the voltage on each resin is equal to the source voltage (V = 30 V)

Therefore we build a circuit with 4 resistors in series, in such a way that

   V = i R

let the voltage

1st resistance

         V = i R

         R₁ = V / i

         R₁ = 14.7 / 1 10⁻³

         R₁ = 14.7 10³ Ω

power is

        P = V i

        P = 14.7 1 10⁻³

        P = 14.7 10⁻³ W = 0.0147 W

a resistance of ⅛ W is indicated

2nd resistance

          R₂ = 8.18 / 1 10⁻³

          R₂ = 8.18 10³ Ω

Power

          P = 8.18 1 10⁻³

          P = 0.00818W

a 1/8 W resistor

3rd resistance

this resistance is calculated in such a way that

          V₁ + V₂ + V₃ = 24.6

          V₃ = 24.6 - V₁ -V₂

          V₃ = 24.6 - 14.7 - 8.18

          V₃ = 1.72 V

          R₃ = 1.72 / 1 10⁻³

          R₃ = 1.72 10³ Ω

           

power

          P = Vi

          P = 1.72 10⁻³

          P = 0.00172 W

a resistance of ⅛ W

To obtain the voltage of 24.6 we use this three resistors together

4th resistance

The value of this resistance is calculated so that the sum of all the voltages reaches the source voltage

           30 = V₁ + V₂ + V₃ + V₄

           V₄ = 30 - V₁ -V₂ -V₃

           V₄ = 30 -14.7 - 8.18 - 1.72

           V₄ = 5.4 V

          R₄ = 5.4 / 1 10⁻³

          R₄ = 5.4 10³ Ω

Power

         P = V i

         P = 5.4 10⁻³

         P = 0.0054 W

⅛ W resistance

The values ​​of these resistance are commercially

Let's check the consumption of the circuit

  R_total = R₁ + R₂ + R₃ + R₄

  R_total = (14.7 + 8.18 + 1.72 + 5.4) 10³

   R_total = 30 10³

the current circulating in the circuit is

     i = V / R_total

     i = 30/30 10³

     i = 1 10⁻³ A

therefore it is within the order requirement.

for connections see attached diagram

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