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Marizza181 [45]
3 years ago
13

A shopper in a supermarket pushes a cart with a force of 35Ndirected at an angle of 25 degree below the horizontal. The forceis

just sufficient to overcome various frictional forces, so thecart moves at constant speed.
(A) Find the work done by the shopper as she moves down a 50.0mlength aisle.
(B) What is the net work done on the cart? why?
(C) The shopper goes down the next aisle, pushing horizontally andmaintaining the same speed as before. If the work don't byfrictional force doesn't chance, would the shopper's applied forcebe larger, smaller, or the same? What about the work done on thecart by the shopper?
Physics
1 answer:
Delicious77 [7]3 years ago
8 0
C the shipped hose down the next aisku pushing horizontally andmanitaining the sama speed as before if the work dont byfrictional Dorce dosent chance would the shopper appplied Dorce be larger smaller or the same what about the work dont on thecart BH the shopper
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A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?
Advocard [28]

Answer:

v=697.2km/h

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

V=\frac{d}{t}

The distance is clearly 1743 km and the time is:

t=2h+30min*\frac{1h}{60min} =2.5h

Thus, the velocity turns out:

v=\frac{1743km}{2.5h}\\ \\v=697.2km/h

Which is a typical velocity for a plane to allow it be stable when flying.

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3 years ago
To determine a waves frequency you must know the??
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Floodplains are most often found for rivers that exist on
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The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
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