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2 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

umka2103 [35]2 years ago

7 0

We must find the slope of the graph first, we can do this by finding two perfect points and inputting those points into the formula y2 - y1/x2 - x1

Perfect point #1: (0,1)

Perfect point #2: (2,5)

As mentioned above, input these numbers into our formula.

5-1 = 4

2 - 0 = 2

4/2 = 2

So, the slope of the graph is 2.

Now, we must find the y-intercept which can be found based on where the line intersects with the y-axis. As we can see, the line intersects at (0,1) therefore the y-intercept of the graph is 1.

We now form a linear equation:

y = 2x + 1

However, since this is linear equality graph we will replace the equal sign with an inequality symbol. The inequality symbol we can use is based on the direction of the shaded area. If shaded up, we use the "greater than symbol", if down then we use the "less than symbol".

The line also matters, if the line is dotted we use the normal inequality symbol, but if it is straight then we use one of the "equal to" inequality symbols.

As for our graph, we have a dotted line with the shaded area upwards. Therefore, we will be using the greater than symbol and not a "equal to" symbol.

So, our answer would be y > 2x + 1

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At 12:00 p.m., Jane leaves her house and drives north to the beach.

almond37 [142]

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2 years ago

Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes

saveliy_v [14]

The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2
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So the LCD here is 10x, so multiply both sides by that to get:
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2 years ago

( – 1, – 5) 7x+2y=13, 4x+4y=14

serious [3.7K]

Answer:

{x,y} = {6/5,23/10}

Step-by-step explanation:

[1] 7x + 2y = 13

[2] 4x + 4y = 14 <---------- linear equations given

Graphic Representation of the Equations : PICTURE
2y + 7x = 13 4y + 4x = 14

Solve by Substitution :

// Solve equation [2] for the variable y

[2] 4y = -4x + 14

[2] y = -x + 7/2

// Plug this in for variable y in equation [1]

[1] 7x + 2•(-x +7/2) = 13

[1] 5x = 6

// Solve equation [1] for the variable x

[1] 5x = 6

[1] x = 6/5

// By now we know this much :

x = 6/5

y = -x+7/2

// Use the x value to solve for y

y = -(6/5)+7/2 = 23/10

// Plug this in for variable y in equation [1]

[1] 7x + 2•(-x +7/2) = 13

[1] 5x = 6

// Solve equation [1] for the variable x

[1] 5x = 6

[1] x = 6/5

// By now we know this much :

x = 6/5

y = -x+7/2

// Use the x value to solve for y

y = -(6/5)+7/2 = 23/10

4 0

2 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

Taylor saw an American alligator at a zoo that measured Ask Your Teacher feet long. The record length of an American alligator i

lianna [129]

Answer:

The record alligator is $6\frac{1}{4}$ feet longer than the alligator Taylor saw.

Step-by-step explanation:

Taylor saw an American alligator at a zoo that measured $12\frac{11}{12}$ feet long. The record length of an American alligator is $19\frac{1}{6}$ feet long. How much longer is the record alligator than the alligator Taylor saw?