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babunello [35]
3 years ago
11

A space shuttle is in orbit about the earth at an altitude where the acceleration due to gravity is 8.70 m/s2. What is the shutt

le's speed at this altitude?
2.65 × 10 3 m/s


7.45 × 10 3 m/s


7.68 × 10 3 m/s


7.91 × 10 3 m/s
Physics
1 answer:
il63 [147K]3 years ago
8 0
The answer is C : 7.68 × 10 3 m/s

8.7 m/s2 = (5.98 * 10 to the 24th power) - this is the mass of earth * (6.67 * 10 to the -11 power) - this is the gravitational constant / v squared = ans (6.77 * 10 to the 6th power

Then do v squared divided by 6.77 * 10 to the 6th power when you calculate it would be 7.68 × 10 3 m/s

- Ask me if you want to get more into depth!
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The answer would be 10ms 2

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In proof testing of circuit boards, the probability that any particular diode will fail is 0.01. Suppose a circuit board contain
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Answer: 2 diodes

Explanation:

Given : In proof testing of circuit boards, the probability that any particular diode will fail is 0.01.

The number of diodes contained by circuit board = 200

Then , the expected number of diodes to fail is given by :-

0.01\times200=2

Therefore, there are 2 diodes that we will expect to fail.

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Is it true or false that air pollution only occurs as a result of human activity
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A nasa spacecraft measures the rate r of at which atmospheric pressure on mars decreases with altitude. the result at a certain
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A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a
Yanka [14]

Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b.  h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

4 0
3 years ago
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