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babunello [35]
2 years ago
11

A space shuttle is in orbit about the earth at an altitude where the acceleration due to gravity is 8.70 m/s2. What is the shutt

le's speed at this altitude?
2.65 × 10 3 m/s


7.45 × 10 3 m/s


7.68 × 10 3 m/s


7.91 × 10 3 m/s
Physics
1 answer:
il63 [147K]2 years ago
8 0
The answer is C : 7.68 × 10 3 m/s

8.7 m/s2 = (5.98 * 10 to the 24th power) - this is the mass of earth * (6.67 * 10 to the -11 power) - this is the gravitational constant / v squared = ans (6.77 * 10 to the 6th power

Then do v squared divided by 6.77 * 10 to the 6th power when you calculate it would be 7.68 × 10 3 m/s

- Ask me if you want to get more into depth!
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Chloe wanted to find out if the color of a food would affect how quickly kindergarten children would eat it for lunch. She belie
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Consider three drinking glasses. All three have thesame area base, and all three are filled to the same depth withwater. Glass A
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The correct answer is C.  All three have equal non-zero pressure

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3 years ago
In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright frin
Natasha2012 [34]

Answer:

y = 0.0233 m

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d = Slit Separation

Now, for initial case:

λ = 425 nm = 4.25  x 10⁻⁷ m

y = 2Δx = 0.0177 m => Δx = 8.85 x 10⁻³ m

Therefore,

8.85 x 10⁻³ m = (4.25 x 10⁻⁷ m)L/d

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3 0
3 years ago
g If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resi
Anettt [7]
<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}

=> R_{X} = \frac{R_1 * R_2}{R_1 + R_2}             ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

R_{X} = \frac{3 * 7}{3 + 7}

R_{X} = \frac{21}{10}

R_{X} = 2.1Ω

(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

4 0
3 years ago
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