A
d
b
b
a
c
c
c
a
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a
b
d
d
a,c
100% 15/15 I promise these are the right answers
Explanation:
electrical potential = (6.6-3.4)/0.20
= 16 uc/m
Answer:

Explanation:
From the question we are told that:
Acceleration 
Displacement 
Initial time 
Final Time 
Generally the equation for Velocity of 1.05 travel is mathematically given by
Using Newton's Law of Motion



Generally the equation for Distance traveled before stop is mathematically given by



Generally the equation for Distance to stop is mathematically given by
Since For this Final section
Final velocity 
Initial velocity 
Therefore
Using Newton's Law of Motion


Giving

Therefore



Generally the Total Distance Traveled is mathematically given by


