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nadya68 [22]
2 years ago
14

A machine has an efficiency of 60%. If the machine is required to overcome a load of 30N with a force of 20N, calculate its mech

anical advantage?​
Physics
1 answer:
skelet666 [1.2K]2 years ago
5 0

Explanation:

eff = m.a/ v.r

m.a = L /E

30/ 20

= 1. 5

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If only 10 pounds is required to lift a 500-lb block, how much chain must be played out to lift the engine 3.0 inches?
adelina 88 [10]

Answer:

150 inches (12.5 ft)

Explanation:

The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.

The following is the equation one needs to solve:

10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\

therefore solving for the distance "x" gives as the answer (in inches):

10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in

which can also be given in feet as: 12.5 ft

3 0
3 years ago
Calculate the frequency of visible light having a wavelength of 410 nm
maria [59]
Given: Wavelength λ = 410 nm  convert to Meters m = 4.10 x 10⁻⁷ m

Speed of light c = 3 x 10⁸ m/s

Required: Frequency  f = ?

Formula: c = λf 

               f = c/λ

               f = 3 x 10⁸ m/s/4.10 x 10⁻⁷ m

               f = 7.32 x 10¹⁴/s  or 732 Thz (Terahertz)
6 0
3 years ago
2. Chickens that are large, castrated males
vagabundo [1.1K]

Answer:

A capon (from Latin: caponem) is a cockerel (rooster) that has been castrated or neutered, either physically or chemically, to improve the quality of its flesh for food, and, in some countries like Spain, fattened by forced feeding.

Explanation:

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3 years ago
A helium nucleus (charge = 2e, mass = 6.63 10-27 kg) traveling at 6.20 105 m/s enters an electric field, traveling from point ci
MA_775_DIABLO [31]

Answer:

v_B=3.78\times 10^5\ m/s

Explanation:

It is given that,

Charge on helium nucleus is 2e and its mass is 6.63\times 10^{-27}\ kg

Speed of nucleus at A is v_A=6.2\times 10^5\ m/s

Potential at point A, V_A=1.5\times 10^3\ V

Potential at point B, V_B=4\times 10^3\ V

We need to find the speed at point B on the circle. It is based on the concept of conservation of energy such that :

increase in kinetic energy = increase in potential×charge

\dfrac{1}{2}m(v_A^2-v_B^2)=(V_B-V_A)q\\\\\dfrac{1}{2}m(v_A^2-v_B^2)={(4\times 10^3-1.5\times 10^3)}\times 2\times 1.6\times 10^{-19}=8\times 10^{-16}\\\\v_A^2-v_B^2=\dfrac{2\times 8\times 10^{-16}}{6.63\times 10^{-27}}\\\\v_A^2-v_B^2=2.41\times 10^{11}\\\\v_B^2=(6.2\times 10^5)^2-2.41\times 10^{11}\\\\v_B=3.78\times 10^5\ m/s

So, the speed at point B is 3.78\times 10^5\ m/s.

7 0
3 years ago
Which of the following tools measures weight? A balance A scale A cyclometer A graduated cylinder
Kazeer [188]
I'm pretty sure its a scale.
8 0
3 years ago
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