Answer:
78.35°
Explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A layer of ethyl alcohol (n = 1.361) is on top of water (n = 1.333). To the nearest degree, at what angle relative to the normal to the interface of the two liquids is light totally reflected?
From Snell's Law,
(ni)/(nr) = Sin (θr) / Sin (θi)
Where
θi = Angle of Incidence
θr = Angle of refraction
ni = Refractive index given for ethyl alcohol
nr = Refractive index of medium from which light is refracted
ni = 1.361
nr = 1.333
, θr = 90° ( Critical Angle is reffered to as Angle of Incidence at refracted angle of 90°) (θi = θc)
(ni)/(nr) = Sin (θr) / Sin (θi)
1.361/ 1.333 = Sin (90°)/ Sin( θc)
1.021= 0.894/ Sin( θc)
Sin( θc)= (0.9794
θc = Sin⁻¹ 0.9794)
θc = 78.35°
Answer:
Following are the option are the correct option to the given question
- Plane landing on an aircraft carrier.
-
Rain sticking to a window.
-
Two train cars coupling together.
Explanation:
In the inelastic collisions is the kinetic energy is not preserved because of the some internal friction.In the elastic collision there is shortage of the kinetic capacity.
- When the airplane is landing it has always been in contact with the surface to relieve the inelastic collision condition.
- When then rain falls the clinging to the door once it intersect with as well so it is satisfied the condition of inelastic collision.
- When the two train or cars collide there is loss of kinetic energy so it is satisfied the condition of inelastic collision.
- All the other option is not the example of inelastic collision that's why they are incorrect option.
Answer:
the answer should be the third statement
Answer:
m₁ / m₂ = 1.3
Explanation:
We can work this problem with the moment, the system is formed by the two particles
The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero
p₀o = m₁ v₁ + m₂ v₂
pf = 0
m₁ v₁ + m₂ v₂ = 0
m₁ / m₂ = -v₂ / v₁
m₁ / m₂= - (-6.2) / 4.7
m₁ / m₂ = 1.3
Another way to solve this exercise is to use the mass center relationship
Xcm = 1/M (m₁ x₁ + m₂ x₂)
We derive from time
Vcm = 1/M (m₁ v₁ + m₂v₂)
As they say the velocity of the center of zero masses
0 = 1/M (m₁ v₁ + m₂v₂)
m₁ v₁ + m₂v₂ = 0
m₁ / m₂ = -v₂ / v₁
m₁ / m₂ = 1.3
Answer:
it depends on the shape size
Hope this helps
Explanation: