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sergeinik [125]
4 years ago
13

Observers in a distant solar system are watching our Sun and using the radial velocity method to try to determine whether the Su

n has planets. Because of the gravitational pull of Jupiter, the observers see the Sun's spectrum slowly redshift and then blueshift by a tiny amount. How long must they observe to see a full cycle?
Physics
1 answer:
Levart [38]4 years ago
8 0

Answer: almost 12 years

Explanation:

Using the radial velocity method, planet hunters can track a sun's spectrum, to determine whether the sun has planets. The spectrum appears first slightly blue-shifted, and then slightly red-shifted. If the shifts are regular, repeating themselves at fixed intervals of days, months, or even years, it  is almost certainly caused by a body orbiting the sun, tugging it back and forth over the course of its orbit. Because of the gravitational pull of Jupiter (about 3,000 times the mass of Earth), In which its average distance from the sun is 480 millions miles and takes nearly 12 years to make one revolution.

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The equation for the conservation of mechanical energy is:
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an object weighs 98 n on earth. How much does it weigh on planet x where the acceleration due to gravity in 6 m/s^2
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Read 2 more answers
A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.
ValentinkaMS [17]

A) 2.03 m/s^2

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

mg sin \theta - \mu_k R = ma (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=22.5^{\circ}

\mu_k = 0.19 is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

R-mg cos \theta =0 (2)

From (2) we find

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2

B) 5.94 m/s

We can solve this part by using the suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

a=2.03 m/s^2

s = 8.70 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s

6 0
3 years ago
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