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Answer:
The maximum height of the arrow is 42 (and the units given for the height)
Explanation:
Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:
When t=0

h(0)=26
If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)
Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:


Then you have to take the derivative, and equals to zero to find t:
-32t+32=0
-32t=32
t=1
That is in the time of 1 second the arrow has its maximum height.
Now you have to replace this value in the original function, to find the height of the arrow:

h(1)=-16+32+36
h(1)=42
Answer:
distance is not a vector. it is scalar
Answer:
<em>Time = 5 seconds</em>
<em>Distance = 50 meters</em>
Explanation:
<u>Constantly Accelerated Motion</u>
When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

And the distance s is

Given the object starts from rest, vo=0 and vf=20 m/s at
. We compute t


Now we compute s


Answer: The closer the planet is to the sun, the faster it travels
Explanation:
The speed of the planets goes down as the chart shows planets farther away from the sun