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Wewaii [24]
3 years ago
10

Explain what causes a change of state. Be sure to include what is happening with the molecules.

Physics
1 answer:
amid [387]3 years ago
5 0
Temperture and speed are the main things 

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If a car is traveling 35 m/s for 200 seconds, how far will the car travel?
zavuch27 [327]
Hey I’m just setting up my profile so I’ll say fast
4 0
3 years ago
Chris shoots an arrow up into the air. The height of the arrow is given by the function h(t) = - 16t2 + 32t + 26 where t is the
seropon [69]

Answer:

The maximum height of the arrow is 42 (and the units given for the height)

Explanation:

Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:

When t=0

h(0)=-16(0^{2})+32(0)+26

h(0)=26

If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)

Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:

h(t)=-16t^{2}+32t+26

h'(t)=-32t+32

Then you have to take the derivative, and equals to zero to find t:

-32t+32=0

-32t=32

t=1

That is in the time of 1 second the arrow has its maximum height.

Now you have to replace this value in the original function, to find the height of the arrow:

h(1)=-16(1^{2})+32(1)+26

h(1)=-16+32+36

h(1)=42

4 0
3 years ago
5 points
Drupady [299]

Answer:

distance is not a vector. it is scalar

5 0
3 years ago
the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
3 years ago
Describe the link between the distance from the Sun and the speed
tresset_1 [31]

Answer: The closer the planet is to the sun, the faster it travels

Explanation:

The speed of the planets goes down as the chart shows planets farther away from the sun

6 0
3 years ago
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