Like-charged bodies will repel each other. When they're brought
closer together, they'll repel each other with even more force.
Answer:
Explanation:
Distance of 2 nd order fringe x₁ = 2 λ D/d [ λ is wave length , D is distance of screen , d is slit distance.
x₁ = 2 x 660 x10⁻⁹x 2.55/.65 x 10⁻³.= 5.17846 x 10⁻³ m.
Distance of fringe for 2nd radiation = 5.178 x 10⁻³ -1.17 x 10⁻³ = 4.008 x10⁻³
4.008 x 10⁻³ = 2 x λ x 2.55/.65 x 10⁻³
λ = 511 nm approx.
.
Answer:
a) 
= 3,375 cm
, b) f₀ = 77.625 cm
Explanation:
The magnification of a telescope is, to see at the far point of vision (infinity image)
m = - f₀ /
The length of the tube is
L = f₀ +
a) The focal length of the eyepiece
L = - m +
L = (1-m)
= L / (1-m)
Let's calculate
= 81.0 / (1 - (-23.0)
= 3,375 cm
b) the focal length of the target
f₀ = -m
f₀ = 23 (3.68)
f₀ = 77.625 cm
The element chlorine has 17 electrons, 17 protons and 18 neutrons....<span> In an atom there is an equal number of electrons and protons. The number of neutrons is found by subtracting the atomic number from the mass number ...
Hope it helps !!!</span>
