Answer:
26.833 N
Explanation:
The computation of the resaltant of two forces is shown below:
Given that
Force A = 12N
Force B = 24N
Based on the above information
Resultant R is
=26.833 N
The outward push of the core created by nuclear fusion and the inward pull of gravity from the core
Answer:
Explanation:
1 ha = 10⁴ m²
1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²
In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³
Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m
Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³
Let Q be the withdrawal in m³
Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶
Q = 26.20 x 10⁶ m³
rate of withdrawal per second
= 26.20 x 10⁶ / 30 x 24 x 60 x 60
= 26.20 x 10⁶ / 2.592 x 10⁶
= 10.11 m³ / s
<h2>
Answer: 450 Bq</h2>
Explanation:
This problem can be solved using the Radioactive Half Life Formula:
(1)
Where:
is the final amount of radioisotope (decay rate)
is the initial amount of the radioisotope
is the time elapsed
is the half life of the radioisotope
Knowing this, let's find from (1):
(2)
(3)
Finally:
>>> This is the decay rate of the radioisotope
Note it is in Becquerels (Bq), which is the derived unit approved by the <u>International System of Units</u> for radioactivity