Question

Calculate The water pressure at the bottom of the Marianas Trench is approxi mately 1,100 kPa. With how much force would the water pressure at the bottom of the Marianas Trench push on a fish with a surface area of 0.50 m^2?

Answer 1

Answer:

Force, F = 550000 N

Explanation:

Given that,

Pressure at the bottom of the Marianas Trench, $P=1100\ kPa=11\times 10^5\ Pa$

Surface area, $A=0.5\ m^2$

We need to find the force with which the water pressure at the bottom of the Marianas Trench push on a fish. Mathematically, the pressure is given by :

$P=\dfrac{F}{A}$

$F=P\times A$

$F=11\times 10^5\ Pa\times 0.5\ m^2$

F = 550000 N

So, the force with which the water pressure at the bottom of the Marianas Trench push on a fish is 550000 N. Hence, this is the required solution.