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3 years ago

Which statement best explains the movement of electric current from the clouds to the ground during a lightning storm? .

Physics

2 answers:

SVEN [57.7K]3 years ago

5 0

Answer:

Correct Answer is option C

Explanation:

Option A cannot be correct because if both earth and clouds are negatively charged then they will repel each other and electron cannot flow through it because electron is negatively charged and it will get attracted towards positively charged terminal. Hence electric current will not flow between them.

Option B

cannot be correct because if both earth and clouds are positively charged then they will repel each other and electron cannot flow through it.Hence electric current will not flow between them.

Option C

It is correct option because flow of current means flow of electron. so electron which are negatively charged particle will move from cloud to positively charged ground.

Option D

If clouds are neutral then electron will not be there and hence current will not flow.

olga2289 [7]3 years ago

3 0

"The <span>ground is positively charged and the clouds are negatively charged " is the statement among the statements given in the question that </span><span>best explains the movement of electric current from the clouds to the ground during a lightning storm. The correct option among all the options that are given in the question is the third option or option "C". </span>

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Explain the difference between potential energy, kinetic energy, and mechanical energy?

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Answer: Potential Eenergy is possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.kinetic energy is energy which a body possesses by virtue of being in motion. Mechanical energy is an energy that is possessed by an object due to its motion or due to its position

Explanation:

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3 years ago

A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier

kolbaska11 [484]

Answer:

2.286 ohm

Explanation:

R1 = 16 ohm

R2 = 8 ohm

R3 = 4 ohm

They all are connected in parallel combination

Let the equivalent resistance is R.

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/16 + 1/8 + 1/4

1/R = (1 + 2 + 4) / 16

1/R = 7 / 16

R = 16/7 = 2.286 ohm

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4 years ago

A massless spring hangs from the ceiling with a small object attached to its lower end. The object is initially held at rest in

navik [9.2K]

Answer:

(A) 1.58 Hz

(B) 0.99 m/s

(C) 0.1 kg

(D) 0.4 m

Explanation:

extension of the spring (x) = 10 cm = 0.1 m

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) force = mg = kx

where m = mass

g = acceleration due to gravity

x = extension

mg = kx

substituting the values 0f g and x we have

9.8m = 0.1k

therefore k = 9.8m/0.1

k = 98m

formula for frequency (f) = $\frac{1}{2π}.\sqrt{\frac{k}{m} }$

inserting the value of spring constant (k) as 98m into the equation above

f = $\frac{1}{2π}.\sqrt{\frac{98m}{m} }$

f = $\frac{1}{2π}.\sqrt{98}$

f = 1.58 Hz

(B) find the speed of the object when it is 8 cm below its initial position

from the conservation of energy,

initial potential energy (U) + kinetic energy (K.E) = 0

( $0.5ky^{2} - mgy) + 0.5mv^{2}$

v = $\sqrt{2gy - \frac{k}{m}.y^{2}}$

where y = position of the spring = 8 cm (0.08m) and k = 98m as in (A) above

v = $\sqrt{2 x 9.8 x 0.08 - \frac{98m}{m}.0.08^{2}}$

v = $\sqrt{1.568 - (98 x 0.0064}$

v = 0.99 m/s

(C) find the mass (m) of the object when an object of mass 300 g is attached to the first object, after which the system oscillates with half the original frequency.

after addition of the 300 g mass

new frequency = half the initial frequency

$\frac{1}{2π}.\sqrt{\frac{k}{m + 300} }$ = 0.5 x $\frac{1}{2π}.\sqrt{\frac{k}{m} }$

$\sqrt{\frac{k}{m + 300} }$ = 0.5 x $\sqrt{\frac{k}{m} }$

$(\sqrt{\frac{k}{m + 300} })^{2} =(0.5 x \sqrt{\frac{k}{m} })^{2}$

$\frac{k}{m + 300} =0.25 x \frac{k}{m}$

$\frac{1}{m + 300} =0.25 x \frac{1}{m}$

0.25 (m + 300) = m

m - 0.25m = 0.25 x 300

m- 0.25m = 75

0.75 m = 75

m = 100 g = 0.1 kg

(D) find the new equilibrium position

from mg = kx we can find the new equilibrium position (x)

where m = m + 300 = m + 0.3 (in kg)

(m+0.3)g = kx

x = $\frac{(m+0.3)g}{k}$

recall that k = 98m

x = $\frac{(m+0.3)g}{98m}$

now substituting the values of m and g into the equation

x = $\frac{(0.1 + 0.3) x 9.8}{98 x 0.1}$

x = 0.4 m

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