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Dvinal [7]
2 years ago
6

Which statement best explains the movement of electric current from the clouds to the ground during a lightning storm? .

Physics
2 answers:
SVEN [57.7K]2 years ago
5 0

Answer:

Correct Answer is option C

Explanation:

Option A cannot be correct because if both earth and clouds are negatively charged then they will repel each other and electron cannot flow through it because electron is negatively charged and it will get attracted towards positively charged terminal. Hence electric current will not flow between them.

Option B

cannot be correct because if both earth and clouds are positively charged then they will repel each other and electron cannot flow through it.Hence electric current will not flow between them.

Option C

It is correct option because flow of current means flow of electron. so electron which are negatively charged particle will move from cloud to positively charged ground.

Option D

If clouds are neutral then electron will not be there and hence current will not flow.

olga2289 [7]2 years ago
3 0
"The <span>ground is positively charged and the clouds are negatively charged " is the statement among the statements given in the question that </span><span>best explains the movement of electric current from the clouds to the ground during a lightning storm. The correct option among all the options that are given in the question is the third option or option "C". </span>
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wo lacrosse players collide in midair. Jeremy has a mass of 120 kg and is moving at a speed of 3 m/s. Hans has a mass of 140 kg
Julli [10]

2.71 m/s fast Hans is moving after the collision.

<u>Explanation</u>:

Given that,

Mass of Jeremy is 120 kg (M_J)

Speed of Jeremy is 3 m/s (V_J)

Speed of Jeremy after collision is (V_{JA}) -2.5 m/s

Mass of Hans is 140 kg (M_H)

Speed of Hans is -2 m/s (V_H)

Speed of Hans after collision is (V_{HA})

Linear momentum is defined as “mass time’s speed of the vehicle”. Linear momentum before the collision of Jeremy and Hans is  

= =\mathrm{M}_{1} \times \mathrm{V}_{\mathrm{J}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{H}}

Substitute the given values,

= 120 × 3 + 140 × (-2)

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Linear momentum after the collision of Jeremy and Hans is  

= =\mathrm{M}_{\mathrm{J}} \times \mathrm{V}_{\mathrm{JA}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{HA}}

= 120 × (-2.5) + 140 × V_{HA}

= -300 + 140 × V_{HA}

We know that conservation of liner momentum,

Linear momentum before the collision = Linear momentum after the collision

80 = -300 + 140 × V_{HA}

80 + 300 = 140 × V_{HA}

380 = 140 × V_{HA}

380/140= V_{HA}

V_{HA} = 2.71 m/s

2.71 m/s fast Hans is moving after the collision.

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2 years ago
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=24*30

=720 hours

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Energy= 7*3

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1 kwh= 0.2

21kwh= x

cross multiply

x=21*0.2

x= $4.2

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