In contrast, extratropical cyclones have their strongest winds near the tropopause, which is about 8 miles above the surface. These differences are due to the tropical cyclone being “warm-core” in the troposphere, whereas extra-tropical cyclones are “warm-core” in the stratosphere and “cold-core” in the troposphere.
To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.
PART A)
The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:
. This is the total charge on the inner surface of the conducting shell.
PART B)
The positive charge (of the same value) on the external surface of the conducting shell is:

The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,



B) It’s material moves due to convection currents.
If current is passed through two parallel conductors in the same direction and the conductors are placed near each other, they will attract each other.
<h3>What is electric current?</h3>
Electric current can be defined as the flow of electrons.
Since electrons are easily removed from atom and are very mobile, the flow of electrons constitute an electric current.
Materials which allow electric current to flow through them are known as conductors. Examples of conductors are metals, and electrolytes.
On the other hand, materials which do not allow electric current to pass through them are known as insulators. Examples of insulators are wood and rubber.
The flow of current is known as electricity.
Parallel conductors with current flowing through them in the same direction are attracted to each other as a result of a magnetic field produced by the flow of current.
In conclusion, conductors allow electric current to pass through and the flow of current through a conductor produces a magnetic field.
Learn more about parallel conductors at: brainly.com/question/17148082
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Answer:
33.83W/m²
Explanation:
The intensity of the speake at the surface is
I = P/A
I = 2.03W / 0.06m²
I = 33.83W/m²