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Anni [7]
3 years ago
13

Click on the boxes below to indicate the number of electrons or protons in each labeled position for a zinc atom (z=30, a=65). P

lease carefully note the specific information requested for the nucleus by the letter designation.

Physics
1 answer:
g100num [7]3 years ago
7 0

Answer:

Name: Zinc

Symbol: Zn

Atomic Number: 30

Atomic Mass: 65.39 amu

Melting Point: 419.58 °C (692.73 K, 787.24396 °F)

Boiling Point: 907.0 °C (1180.15 K, 1664.6 °F)

Number of Protons/Electrons: 30

Number of Neutrons: 35

Classification: Transition metal

Crystal Structure: Hexagonal

Density at 293 K: 7.133 g/cm3

Color: bluish

('lil long, sorry)

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What is the net magnetic flux through any closed surface?
Paul [167]

Answer:

The net magnetic flux through any closed surface must always be zero.

3 0
3 years ago
the kinetic energy of an object with mass m moving with a velocity of 5 m/s is 25 j what will be its kinetic energy when its vel
Dmitriy789 [7]

Answer:

100 J, 225 J

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is the velocity of the object

In this problem, the initial kinetic energy of the object is

K = 25 J

Then, the velocity is doubled, which means

v' = 2v

Therefore, the new kinetic energy will be

K'=\frac{1}{2}m(2v)^2 = 4(\frac{1}{2}mv^2)=4K

Therefore, the kinetic energy has quadrupled:

K' = 4(25)=100 J

Later, the velocity is tripled, which means

v'' = 3v

Therefore, the new kinetic energy will be

K''=\frac{1}{2}m(3v)^2 = 9(\frac{1}{2}mv^2)=9K

Therefore, the kinetic energy has increased by a factor of 9:

K' = 9(25)=225 J

4 0
3 years ago
A 0.500-kg block, starting at rest, slides down a 30.0° incline with static and kinetic friction coefficients of 0.350 and 0.250
Leviafan [203]

Answer:x=23.4 cm

Explanation:

Given

mass of block m=0.5 kg

inclination \theta =30

coefficient of static friction \mu =0.35

coefficient of kinetic friction \mu _k=0.25

distance traveled d=77.3 cm

spring constant k=35 N/m

work done by gravity+work done by friction=Energy stored in Spring

mg\sin \theta d-\mu _kmg\cos \theta d=\frac{kx^2}{2}

mgd\left ( \sin \theta -\mu _k\cos \theta \right )=\frac{kx^2}{2}

0.5\times 9.8\times 0.773\left ( \sin 30-0.25\cos 30\right )=\frac{35\times x^2}{2}

x=\sqrt{\frac{2\times 0.5\times 9.8\times 0.773(\sin 30-0.25\times \cos 30)}{35}}

x=0.234 m

x=23.4 cm

6 0
3 years ago
A boat floats in water a. Archimedes b. Bernoulli c. Density d. Pascal e. Pressure
Ivenika [448]
The answer is Density !, Do you also need an example ?

Rate this the brainliest answer , Thank youuu !
7 0
3 years ago
Read 2 more answers
Find the work w1 done on the block by the force of magnitude f1 = 95.0 n as the block moves from xi = -5.00 cm to xf = 4.00 cm .
Vlad [161]
<h3><u>Answer;</u></h3>

= 8.55 Joules

<h3><u>Explanation;</u></h3>

Work done is the product of force and the distance moved by an object.

Work done = Force × distance

Force = 95 Newtons

Distance = X2 -X1

               = 4 - (-5)

               = 9 cm

Thus;

work done = 95 × 9/100

                  <u>= 8.55 Joules </u>

5 0
3 years ago
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