Answer:
Step-by-step explanation:
![(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B%28x%2B3%29%7D%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5C%5C%5C%5C%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%5B1%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5D)
Therefore,
Answer:
1/25 ; 3/20 ; 3/50
Step-by-step explanation:
Total number of stickers :
(10 + 15 + 25) = 50 stickers
Probability = required outcome / Total possible outcomes
a. Selecting blue and blue stickers
P(First blue) = 10/50 = 1/5
P(second blue) = 10/50 = 1/5
1/5 * 1/5 = 1 / 25
b. Selecting one red sticker and then one orange sticker
P(First red) = 15/50 = 3/10
P(second orange) = 25/50 = 1/2
3/10 * 1/2 = 3 /20
Selecting one red sticker and then one blue sticker
P(First red) = 15/50 = 3/10
P(second blue) = 10/50 = 1/5
3/10 * 1/5 = 3 / 50
She can have 3 groups of tens and 8 groups of ones
Factors of 38
1, 2, 19, 38
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1×38
2×19
Factors of 59
1, 59
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Common factors for 38 and 59
1 is the only common factor
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GCF of 38 and 59
1 is the both the common and GCF of 38 and 59
Ni because if you divide or mulriply the denominator you have to multiply or divide the numerator by the same amount. It is not possible dince you can divide the denominator by 2 to get 3 but you cant divude 5 by 2 and get an evn number
