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3 years ago

F(x)=√(10-3x) find the formula

1 answer:

8 0

Let y=f(x)
y=sqrt(10-3x)
you want to make x the subject

square both sides
y²=10-3x
3x=10-y²
x=(10-y²)/3

now replace y with x
f^-1(x)=(10-x²)/3

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Answer: In quadrant 1 or quadrant 2.

Step-by-step explanation:

We have the numbers:

x = c + di

y = e + fi

where c, d, e and f are real positive numbers.

the product of these numbers is:

x*y = (c + di)*(e + fi) = c*e + c*fi + d*ei ´+d*f*i^2

x*y = c*e - d*f + (c*f + d*e)i

where I used that i^2 = -1

knowing that c,f, d and e are positive numbers, then the imaginary part of the product must be always positive.

For the real part, we have c*e - d*f, that can be positive o negative depending on the values of c, e, d, and f.

So we have that the product must lie always in one of the upper two quadrants, quadrant 1 or quadrant 2 because the imaginary part is always positive and the real part can be positive or negative.

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3 years ago

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Andreyy89

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Each of the terms in the expression represents a different transformation of a different trig function. Expressing those as the same trig function can make it easier to find the sum.

We can start with the identity ...

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Substituting the argument of the cosine function in the given expression, we have ...

cos(π/2 -θ) = sin((π/2 -θ) +π/2) = sin(π -θ) = -sin(θ -π)

The first term, sin(π +θ), is a left-shift of the sine function by 1/2 cycle, so can be written ...

sin(π +θ) = -sin(θ)

The second term is the opposite of a right-shift of the sine function by 1/2 cycle, so can be written ...

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