A force in the negative x-direction is applied for 27 ms to a 0.4 kg mass initially moving at +14 m/s in the x-direction. The fo
1 answer:
It is given that,
Mass of the object, m = 0.5 kg
A force is applied for 27 ms.
Initial speed of the object, u = +14 m/s
Impulse of the force, J = 32.4 N-s (in negative direction)
Let v is the velocity of mass in x direction. We know that the impulse of an object is equal to the change in momentum. It is given by :
v = -67 m/s
So, the velocity of the mass is 67 m/s and it is in negative x direction.
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Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = = sin θ
sin θ = y / L
we substitute
= m λ
with the initial data we look for the distance between the lines
d =
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Answer:
Number of electrons, n = 6
Explanation:
Total charge in a single droplet,
The measured charge of any single droplet,
Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :
n = 6
So, there are 6 electrons contained within the drop. Hence, this is the required solution.