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VikaD [51]
3 years ago
6

Find the surface area of a cylinder with a base radius of 3 in and a height of 8 in.

Mathematics
1 answer:
Tom [10]3 years ago
5 0

Answer:

66π in²

Step-by-step explanation:

Area of one circular base: πr² ⇒ π3² ⇒ 9π

Area of the two circles: 9π + 9π = 18π

We know that the length of the rectangle is 8 in, but we still have to find width. The width of the rectangle is the circumference of either circle:

Width of rectangle: 2πr ⇒ 2π3 ⇒ 6π

Area of rectangle: 6π · 8 = 48π

Total Surface Area: 48π + 18π = 66π in²

Total Surface Area (using the π symbol on a calculator)≈ 207.345 in²

Hopefully this helps!

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<u>-x      </u>   <u> -x         </u>                              <u>     +12 </u>  <u>+12 </u>

     3 < 3x - 12                 or           4x        < 32

<u>    +12</u>   <u>     +12  </u>                            <u> ÷4        </u>   <u>÷4  </u>

    15 < 3x                       or              x        <  8

<u>    ÷3</u>    <u>÷3 </u>

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5 < x < 8

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