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3 years ago

Find the surface area of a cylinder with a base radius of 3 in and a height of 8 in.

Mathematics

1 answer:

Tom [10]3 years ago

5 0

Answer:

66π in²

Step-by-step explanation:

Area of one circular base: πr² ⇒ π3² ⇒ 9π

Area of the two circles: 9π + 9π = 18π

We know that the length of the rectangle is 8 in, but we still have to find width. The width of the rectangle is the circumference of either circle:

Width of rectangle: 2πr ⇒ 2π3 ⇒ 6π

Area of rectangle: 6π · 8 = 48π

Total Surface Area: 48π + 18π = 66π in²

Total Surface Area (using the π symbol on a calculator)≈ 207.345 in²

Hopefully this helps!

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Which answer best describes the solution to the equation

german

Let's check
3m - 9 = 9+3m
collect like terms
3m -3m = 9 + 9
0m = 18
which is not possible, so it will not have any solutions

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4 years ago

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The point R is halfway between the integers on the number line below and represents the number ____. (Use the hyphen for negativ

PSYCHO15rus [73]

I guess ur just gunna have to bear with whatever until we have a multiple choice answer selection.

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3 years ago

I put a picture<br><br> —PLEASE HELP

Karo-lina-s [1.5K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

$side \times side$

$x \times x$

${x}^{2}$

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

${x}^{2} = \dfrac{1}{4}$

$x = \sqrt{ \dfrac{1}{2} \times \dfrac{1}{2} }$

$x = \dfrac{1}{2} \: \: feet$

It's time to find the volume of cube that is ~

$(side) {}^{3}$

So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

${ \bigg(\dfrac{1}{2} \bigg) }^{3}$

$\dfrac{1}{8} \: \: ft {}^{3}$

Hence, the required 1/8 or 0.125 ft³

I hope it helped ~

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3 years ago

Read 2 more answers

Henry ran five races, each of which was a different positive integer number of

dolphi86 [110]

Answer:

10 miles.

Step-by-step explanation:

Let x be the number of miles on Henry's longest race.

We have been given that Henry ran five races, each of which was a different positive integer number of miles.

We can set an equation for the average of races as:

$\frac{\text{The sum distances of 5 races}}{5}=4$

As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.

Now let us substitute the distances of 5 races as:

$\frac{1+2+3+4+x}{5}=4$

$\frac{10+x}{5}=4$

Let us multiply both sides of our equation by 5.

$\frac{10+x}{5}*5=4*5$

$10+x=20$

Let us subtract 10 from both sides of our equation.

$10-10+x=20-10$

$x=10$

Therefore, the maximum possible distance of Henry's longest race is 10 miles.

7 0

3 years ago

The set of points in space that are a given distance from a given point is called a(n) __________.

Marrrta [24]

The answer would be B. Edge

The set of points in space that are a given distance from a given point is called an <u>Edge.</u>

D would be incorrect since it doesn’t have any edges and is like a circle but is 3D. A cylinder is also incorrect since it has curves from top to bottom. C is also incorrect since it only shows one side, which is called the face. That leaves you with edge which would be the correct answer.

Hope this helps! :3

8 0

3 years ago