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3 years ago

A circuit has a voltage drop of 24.0 V across a 30.0 resistor that carries a

Physics

2 answers:

Ilya [14]3 years ago

7 0

Answer:

19.2

Explanation:

beks73 [17]3 years ago

6 0

(A) 19.2 W

<u>Explanation:</u>

Given-

Voltage drop, V = 24 V

Resistor = 30Ω

Current, I = 0.8 A

Power, P = ?

We know,

P = VI

P = 24 (0.8)

P = 19.2 W

Therefore, the power conducted by the resistor is 19.2 W

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2.)

Oduvanchick [21]

Answer:

$-22.7 m/s^2$

Explanation:

This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem,

u = 27.8 m/s

v = 0

s = 17 m

Solving for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{0-27.8^2}{2(17)}=-22.7 m/s^2$

4 0

3 years ago

How can you increase the potential energy of a bouncing ball

ad-work [718]

Answer:

When you lift the ball, you are doing work to increase its gravitational potential energy. When you then release the ball, gravitational energy is transformed into kinetic energy as the ball falls. When the ball hits the floor, the ball's shape changes as it flattens against the floor.

Explanation:thats should be the way^^ in explaining

7 0

3 years ago

A horizontal uniform bar of mass 2.5 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t

11Alexandr11 [23.1K]

Answer: I am not sure if you wanted me to answer this or not.

Explanation:

6 0

2 years ago

A spring of constant 20 N/m has compressed a distance 8 m by a(n) 0.3 kg mass, then released. It skids over a frictional surface

Fiesta28 [93]

Answer:

$X_2=25.27m$

Explanation:

Here we will call:

1. $E_1$ : The energy when the first spring is compress

2. $E_2$ : The energy after the mass is liberated by the spring

3. $E_3$ : The energy before the second string catch the mass

4. $E_4$ : The energy when the second sping compressed

so, the law of the conservations of energy says that:

1. $E_1 = E_2$

2. $E_2 -E_3= W_f$

3. $E_3 = E_4$

where $W_f$ is the work of the friction.

1. equation 1 is equal to:

$\frac{1}{2}Kx^2 = \frac{1}{2}MV_2^2$

where K is the constant of the spring, x is the distance compressed, M is the mass and $V_2$ the velocity, so:

$\frac{1}{2}(20)(8)^2 = \frac{1}{2}(0.3)V_2^2$

Solving for velocity, we get:

$V_2$ = 65.319 m/s

2. Now, equation 2 is equal to:

$\frac{1}{2}MV_2^2-\frac{1}{2}MV_3^2 = U_kNd$

where M is the mass, $V_2$ the velocity in the situation 2, $V_3$ is the velocity in the situation 3, $U_k$ is the coefficient of the friction, N the normal force and d the distance, so:

$\frac{1}{2}(0.3)(65.319)^2-\frac{1}{2}(0.3)V_3^2 = (0.16)(0.3*9.8)(2)$

Volving for $V_3$ , we get:

$V_3 = 65.27 m/s$

3. Finally, equation 3 is equal to:

$\frac{1}{2}MV_3^2 = \frac{1}{2}K_2X_2^2$

where $K_2$ is the constant of the second spring and $X_2$ is the compress of the second spring, so:

$\frac{1}{2}(0.3)(65.27)^2 = \frac{1}{2}(2)X_2^2$

solving for $X_2$ , we get:

$X_2=25.27m$

3 0

3 years ago

Which describes the formation of Horizon B?

Finger [1]

c-undergoes the most change

Explanation:

Horizon B is the layer in a soil profile that has undergone the most change.

A section through a typical soil reveals many of the different layers.

The rock layers are divided into sections which are called horizons.

Horizon O is the organic matter

Horizon A is the top soil

Horizon B is the subsoil.

The subsoil of horizon B is the layer that undergoes the most change. It materials are constantly being leached away from this layer by chemical weathering. Some of the processes here accounts for it typical reddish brown color.

The rock layer here is rich in iron oxide and washed down minerals. It lacks significant amount of humus.

learn more:

Soil formation brainly.com/question/2473178

#learnwithBrainly

5 0

4 years ago