Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
De broglie wavelength is given as
Part b)
By principle of uncertainty we know that
Part c)
As we know that
also we know
now we have
A ball drops some distance and gains 30 J of kinetic energy. How much gravitational potential energy did the ball start with? Do
1 answer:
Answer:
The gravitational potential energy of the ball is more than 30 J.
Explanation:
Given that,
Gains kinetic energy = 30 J
We need to calculate the gravitational potential energy
According to law of conservation of energy
If there is no air resistance then the potential energy of the ball fully converted into kinetic energy.
If the air resistance is considered then the potential energy used to do work against air resistance.
According to question,
A ball drops some distance and gains 30 J of kinetic energy and considers air resistance then 30 J of potential energy can be loosed by the ball.
Hence, The gravitational potential energy of the ball is more than 30 J.
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The energy of the baby is gravitational potential energy, and it is equal to the weight of the baby times its height from the ground:
where
mg=20 N is the weight (the mass times the gravitational acceleration)
h=1.5 m is the height from the ground
If we plug the numbers into the equation, we find
where
mg=20 N is the weight (the mass times the gravitational acceleration)
h=1.5 m is the height from the ground
If we plug the numbers into the equation, we find
Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion
h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.