Answer:
b.false i think
Explanation:
i hope i am correct and helps you
Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
Answer:
0.0198 dollars
Explanation:
We first obtain the total energy drawn by the light bulb in kilowatt-hour (kW-hr) using the following relationship;
Energy = power rating x time
Given;
power rating = 60W,
time = 3hrs
Therefore,
Energy consumed = 60W x 3hr
Energy consumed = 180W-hr = 0.18kW-hr
We then multiply this energy in kW-hr by he amount charged per unit kW-hr as follows;
Given that 1kW-hr= 0.11 dollars
0.18kW-hr = 0.18 x 0.11
= 0.0198 dollars
Using the given formula with v0=56 ft/s and h=40 ft
h = -16t2 + v0t
40 = -16t2 + 56t
16t2 - 56t + 40 = 0
Solving the quadratic equation:
t= (-b+/-(b^2-4ac)^1/2)/2a = (56+/-((-56)^2-4*16*40)^1/2)/2*16 = (56 +/- 24) / 32
We have two possible solutions
t1 = (56+24)/32 = 2.5
t2 = (56-24)/32 = 1
So initially the ball reach a height of 40 ft in 1 second.
