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ruslelena [56]
3 years ago
9

Please help me quickly!!!

Physics
1 answer:
vichka [17]3 years ago
6 0
Hey! So referring to the data the thing we can clearly see is that in a vacuum, everything, regardless of its mass, falls at the same speed.

Acceleration is often confused with speed, or velocity, but the difference is, acceleration by definition is the rate of which an object falls with respect to its mass and time.

Every single thing in the world falls at the same acceleration, this is because of gravity. The difference is the speed of which it falls. In space, there is not any gravity, and so, the objects are able to fall at the same speed regardless of their mass.
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A toy rocket, launched from the ground, rises vertically with an acceleration of 28 m/s 2 for 9.7 s until its motor stops. Disre
vredina [299]

Answer:

5080.86m

Explanation:

We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:

y_1=y_{01}+v_{01}t+\frac{a_1t^2}{2}

v_1=v_{01}+a_1t

We must consider that it's launched from the ground (y_{01}=0m) and from rest (v_{01}=0m/s), with an upwards acceleration a_{1}=28m/s^2 that lasts a time t=9.7s.

We calculate then the height achieved in part 1:

y_1=(0m)+(0m/s)t+\frac{(28m/s^2)(9.7s)^2}{2}=1317.26m

And the velocity achieved in part 1:

v_1=(0m/s)+(28m/s^2)(9.7s)=271.6m/s

We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (y_{02}=1317.26m) and its initial velocity is the one achieved in part 1 (v_{02}=271.6m/s), now in free fall, which means with a downwards acceleration a_{2}=-9,8m/s^2. For the data we have it's faster to use the formula v_f^2=v_0^2+2ad, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:

v_{02}^2+2a_2(y_2-y_{02})=v_2^2=0m/s

Then, to get y_2, we do:

2a_2(y_2-y_{02})=-v_{02}^2

y_2-y_{02}=-\frac{v_{02}^2}{2a_2}

y_2=y_{02}-\frac{v_{02}^2}{2a_2}

And we substitute the values:

y_2=y_{02}-\frac{v_{02}^2}{2a_2}=(1317.26m)-\frac{(271.6m/s)^2}{2(-9.8m/s^2)}=5080.86m

3 0
3 years ago
Jill can use a force of 12.0 N to lift a single box up 5.00 m. How many of these boxes must she lift it in a minute to use 60.0
Mama L [17]

Answer:

60 boxes

Explanation:

The work done by lifting a single box is equal to the force applied (the weight of the box) times the displacement of the box:

W_1 = Fd=(12.0 N)(5.00 m)=60 J

Power is related to the work done by the equation:

P=\frac{W}{t}

where W is the work done and t is the time. In this problem, we are told that the power used is P=60.0 W, while the time taken is t = 1 min = 60 s, so the total work done must be

W=Pt=(60.0 W)(60 s)=3600 J

Therefore, the number of boxes that she has to lift in order to use this power is the total work divided by the work done in lifting each box:

N=\frac{W}{W_1}=\frac{3,600 J}{60 J}=60

5 0
3 years ago
PLS HELP ME I WILL GIVE YOU BRAINLIEST
ElenaW [278]
3. Millions of years ago, the Earth was not divided into 7 continents. It was only a very large land mass, the scientists named that one land mass “Pangaea”
4. If the tectonic plates are disturbed, they can cause mass earthquakes and tsunamis.
5. The ring of fire is a massive collection of volcanoes under the pacific ocean. They all form the shape of a ring, hence the name.
SORRY, I COULDNT ANSWER THE FIRST TWO QUESTIONS.
8 0
3 years ago
Read 2 more answers
How much energy is required to heat 70 g of water at 20°C to boiling
choli [55]

Answer:

Q=23,430J

Explanation:

Hello,

In this case, since we compute the required energy via:

Q=mC\Delta T

Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:

\Delta T=100-20=80\°C

Therefore, the energy turns out:

Q=70g*4.184\frac{J}{g\°C}*80\°C\\ \\Q=23,430J

Best regards.

3 0
3 years ago
A repelling force occurs between two charged objects when the charges are of Equal magnitude. Equal magnitude. a Unequal magnitu
Ahat [919]

Answer:

c Like/same signs

Explanation:

A repelling force occurs between two or more charged objects with the charges are of like or same sign.

  • According to Coulombs law, like charges repel on another, unlike charges attracts on another.
  • If a positive charge comes into the vicinity of another positive charge, there will be repulsion.
  • When oppositely charge species are brought near each other, there is an attraction.

Therefore, repulsion occurs when like charges are brought close to each other.

3 0
2 years ago
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