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4 years ago

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Please help me quickly!!!

1 answer:

vichka [17]4 years ago

6 0

Hey! So referring to the data the thing we can clearly see is that in a vacuum, everything, regardless of its mass, falls at the same speed.

Acceleration is often confused with speed, or velocity, but the difference is, acceleration by definition is the rate of which an object falls with respect to its mass and time.

Every single thing in the world falls at the same acceleration, this is because of gravity. The difference is the speed of which it falls. In space, there is not any gravity, and so, the objects are able to fall at the same speed regardless of their mass.

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A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s

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The energy and the wavelength of the photon are 1.546 MeV and $8.036\times10^{-13}\ m$ .

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant $h = 6.626\times10^{−34}\ J.s$

Speed of light $c=2.998\times10^{8}\ m/s$

Mass of electron $m_{e}=9.109\times10^{-31}\ kg$

Charge $q=1.602\times10^{-19}\ C$

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

$E=m_{0}c^2$

$E=9.109\times10^{-31}\times(3\times10^{8})^2$

$E=8.198\times10^{-14}\ J$

Energy in eV

$E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}$

$E=512375\ eV$

$E=0.512\ MeV$

The total energy of photon

$TE=2(E+K.E)$

$TE=2(0.512+0.261)$

$TE=1.546\ MeV$

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

$\lambda=\dfrac{hc}{E}$

Put the value into the formula

$\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}$

$\lambda=8.036\times10^{-13}\ m$

Hence, The energy and the wavelength of the photon are 1.546 MeV and $8.036\times10^{-13}\ m$ .

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3 years ago