Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.
Answer:
It's choice B.
Step-by-step explanation:
When r= -11,
x^2 + 8x - 33 = (-11)^2 - 88 - 33
= 121 - 88 - 33
= 0
- so x = -11 gives a zero value and is a solution to the equation.
Answer:

Step-by-step explanation:
We are given the following in the question:
A(1, 1), B(2, 4), C(4, 2)
i) Slope of AB

Thus, slope of AB is 3.
ii) Point slope form
The point slope form of a line can be written as:

The point intercept form of line can be written as:

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB
Putting values, we get,

which is the required slope intercept equation of line p.
Answer:
<h2>IT'S 22 JUST FOUND OUT </h2>
Step-by-step explanation:
Answer:

(If that closed circle is an open circle, please let me know because that means something totally different)
Step-by-step explanation:
I think you are given:
and that you are asked to find:

That operation means multiplication. (Let me know if is an open circle because that means something difference).

Distribute:

Reorder a little (commutative property):
