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m_a_m_a [10]
3 years ago
12

Wave energy from the ocean can be harnessed to power generators to make electricity. Energy from rides can also be used to make

electricity. How would you categorize these two sources of energy
Chemistry
2 answers:
Cloud [144]3 years ago
8 0

Answer:

The energy sources described are forms of <em>kinetic energy</em>

Explanation:

<u>Kinetic energy, K.E</u> can be defined as the energy a body possesses due to its state of motion. It is defined by the work done in accelerating a body of known mass at a given starting velocity.

Ocean wave energy is form of the kinetic energy which occurs from the movement of water waves, as the waves are mostly caused by blowing winds over the ocean surface.

Likewise, the energy from rides such as spinning wheels can be used to power turbines.

All these are forms of energy in motion.

Brrunno [24]3 years ago
7 0

Answer:

Kinetic

Explanation:

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Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
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<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

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Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

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