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vitfil [10]
3 years ago
7

Which solution has the higher boiling point: 42.0 g c2h6o2 in 0.500 kg of h2o or 35.0 g nacl in 0.500 kg of h2o?

Chemistry
1 answer:
Lelechka [254]3 years ago
6 0

Answer:

  • The NaCl solution will have higher boiling point.

Explanation:

  • C2H6O2 is a molecular substance. Meaning that when it dissolves it will remain this way:

                                  C2H6O2 ---------> C6H12O6 (aq)  

  • Sodiumchloride (NaCl) is an ionic substance. Meaning that when it dissolves, it will create ions:

                                   NaCl(s)-------> Na+(aq) + Cl- (aq)

Conclusion:

  • NaCl is an ionic compound and C2H6O2 is a molecular compound. Ionic compounds have higher boiling points than molecular compounds. Therefore, NaCl will have the higher boiling point.
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What is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen​
levacccp [35]

Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

5 0
3 years ago
Which kind of URL suffix would you most likely find attached to a site maintained by the Red Cross?
Ostrovityanka [42]
It would most likely be .org or .com :)
Your welcome :D
7 0
3 years ago
In the EXPLORE section of your lesson 4.08 on Potential energy there were several animations to watch that provided a graphic il
Lunna [17]

Answer:

This is because no energy is being created or destroyed in this system

Explanation:

I think this is correct? I hope it helps.        

7 0
3 years ago
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How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this
KiRa [710]

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = \frac{mass}{molar mass}

Number of moles of acetone = \frac{31.5}{58.08}

Number of moles  of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

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D 6) Select True or False.
Mama L [17]

Answer:

true

Explanation:

6 0
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