No. The forces of gravity between them would remain unchanged after those three changes.
After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward.
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is

at every point of the motion, and therefore also when the baseball is at its highest point.
The impulse given to the ball is equal to the change in its momentum:
J = ∆p = (0.50 kg) (5.6 m/s - 0) = 2.8 kg•m/s
This is also equal to the product of the average force and the time interval ∆t :
J = F(ave) ∆t
so that if F(ave) = 200 N, then
∆t = J / F(ave) = (2.8 kg•m/s) / (200 N) = 0.014 s
Answer: 10.34
Explanation:
Given
graph for a particle is given
angle turned by the particle in radians is given by the area under
graph
The area is given by

Revolutions(N) made by the object is given by

Answer:78 N
Explanation:Impulse=Force*time
=39*2 =78 Ns