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SashulF [63]
2 years ago
6

The graph represents the reaction 2H20+ 02 2H2O2 as it reaches

Physics
1 answer:
Phantasy [73]2 years ago
3 0

Answer:

C. at point 2 the concentrations of H20...O2... & H2 are all changing

toward their equilibrium concentrations

D. at point 1 more reactants are converted to products than

products are converted to reactants

Explanation:

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Answer fast plz<br> ....................
luda_lava [24]

Answer:

114 m/s

Explanation:

see the image below

8 0
3 years ago
11. Will the cube in#10 float in water? Will it float in benzene?
densk [106]
Where is the cube I don't see any picture?
5 0
4 years ago
The density of blood is 1.05 kg/m3, find the mass of a bag of blood for a transfusion, if the volume is 1.5 m3.
hoa [83]

(1.5 m^3) • (1.05 kg/m^3) = 1.575 kg.  That's quite a bag you've got there !  1 m^3 is like 264 gallons of blood.  Hope the poor patient survives the transfusion. Also, the actual density of blood is around 1.05 g/cm^3, or 1050 kg/m^3. The blood they're giving the guy in this question is about 18% less dense than the AIR in his hospital room, and they're pumping 264 gallons of it into him. Maybe THAT'S his whole problem.

6 0
3 years ago
Read 2 more answers
A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it
mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm

r = 0.145\ cm = 0.145\times 10^{-2}\ m

Charge ,

Q = 30.0\ pC=30\times 10^{-12}

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}

Where,  

V= Electric potential,  

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge  

r = Radius  

Substituting the values we get

V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}

V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0
4 years ago
The diagram below shows a desert food web. How will a large decrease in the number of rats impact the food web shown above?
Nookie1986 [14]

Answer:

Decrease of snake, coyote, and hawk population. Increase of sagebrush and cacti.

Reasons:

The rats are aten by the snake coyote and hawks so if a food source is taken from them they are going to have to fight more for food. The rats eat the sagebrush and cacti so if they arent getting eaten as much, they have mroe ime to produce.  

7 0
3 years ago
Read 2 more answers
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